Answer:
The value is 
Explanation:
From the question we are told that
mass of carbon dioxide produced by one gallon of gasoline is 
The number of cars is 
The distance covered by each car is 
The rate is 
Generally the amount of gasoline used by one car is mathematically represented as

=> 
=> 
Generally the amount of gasoline used by N cars is

=> 
=> 
Generally the annual production of carbon dioxide is mathematically represented as

=> 
=> 
Answer:
The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).
Answer:
It is mostly water (up to 95% by volume), and contains dissolved proteins (6–8%) (e.g. serum albumins, globulins, and fibrinogen), glucose, clotting factors, electrolytes (Na+, Ca2+, Mg2+, HCO3−, Cl−, etc.), hormones, carbon dioxide (plasma being the main medium for excretory product transportation) and oxygen.
hope this helps :)
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Answer:
a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.
Explanation:
The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).
Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.
<em>Which statement below explains that?</em>
<em>a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.</em> YES.
<em>b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.</em> NO.
<em>c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.</em> NO.
<em>d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.</em> NO.
Answer:
43.2 moles of carbon dioxide are required and 421g of glucose could be produced
Explanation:
Based on the reaction:
6CO2 + 6H2O → C6H12O6 + 6O2
1 mole of glucose, C6H12O6, requires 6 moles of carbon dioxide. 7.2moles of glucose requires:
7.2mol C6H12O6 * (6mol CO2 / 1mol C6H12O6) =
<h3>43.2 moles of carbon dioxide are required</h3><h3 />
618g of CO2 -Molar mass: 44.01g/mol- are:
618g * (1mol / 44.01g) = 14.04moles CO2
Moles C6H12O6:
14.04moles CO2 * (1mol C6H12O6 / 6mol CO2) = 2.34moles C6H12O6
Mass glucose -Molar mass: 180.156g/mol-
2.34moles C6H12O6 * (180.156g / mol) =
<h3>421g of glucose could be produced</h3>