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RUDIKE [14]
3 years ago
13

Select the correct answer.

Chemistry
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

Vanadium(V) oxide is the inorganic compound with the formula V2O5. Commonly known as vanadium pentoxide,

Explanation:

then it is answer D

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One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, which is a greenhouse gas; that i
vagabundo [1.1K]

Answer:

The value is U  =1.3908 *10^{11} \  kg

Explanation:

From the question we are told that

mass of carbon dioxide produced by one gallon of gasoline is m  =  9.50 \  kg

The number of cars is N =  40 \  million =  40 *10^{6} \  cars

The distance covered by each car is d =  7930 \ mi

The rate is R  =  23.6 \  mi/ gallon

Generally the amount of gasoline used by one car is mathematically represented as

G  =  \frac{d}{R}

=> G  =  \frac{7930}{23.6}

=> G  =   366 \  gallons

Generally the amount of gasoline used by N cars is

H  =  N  *  G

=> H  =  40*10^{6}  *  366

=> H  = 1.464*10^{10} \  gallons

Generally the annual production of carbon dioxide is mathematically represented as

U  =  m *  H

=> U  =9.50 *   1.464*10^{10}

=> U  =1.3908 *10^{11} \  kg

8 0
4 years ago
If pressure is held constant and a gas is heated, what will happen to the volume of the gas?
Galina-37 [17]

Answer:

The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).

5 0
3 years ago
Which of the following contains plasma?
UNO [17]

Answer:

It is mostly water (up to 95% by volume), and contains dissolved proteins (6–8%) (e.g. serum albumins, globulins, and fibrinogen), glucose, clotting factors, electrolytes (Na+, Ca2+, Mg2+, HCO3−, Cl−, etc.), hormones, carbon dioxide (plasma being the main medium for excretory product transportation) and oxygen.

hope this helps :)

can i pls have a brainilist!

3 0
3 years ago
Read 2 more answers
The heating curve for a sample of pure ethanol shows the slope of the line for gaseous state is greater than the slope of the li
Agata [3.3K]

Answer:

a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.

Explanation:

The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).

Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.

<em>Which statement below explains that?</em>

<em>a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.</em> YES.

<em>b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.</em> NO.

<em>c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.</em> NO.

<em>d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.</em> NO.

3 0
3 years ago
Blank moles of carbon dioxide are required to make 7.2 moles of glucose. A plant using 618 grams of carbon dioxide and plenty of
Virty [35]

Answer:

43.2 moles of carbon dioxide are required and 421g of glucose could be produced

Explanation:

Based on the reaction:

6CO2 + 6H2O → C6H12O6 + 6O2

1 mole of glucose, C6H12O6, requires 6 moles of carbon dioxide. 7.2moles of glucose requires:

7.2mol C6H12O6 * (6mol CO2 / 1mol C6H12O6) =

<h3>43.2 moles of carbon dioxide are required</h3><h3 />

618g of CO2 -Molar mass: 44.01g/mol- are:

618g * (1mol / 44.01g) = 14.04moles CO2

Moles C6H12O6:

14.04moles CO2 * (1mol C6H12O6 / 6mol CO2) = 2.34moles C6H12O6

Mass glucose -Molar mass: 180.156g/mol-

2.34moles C6H12O6 * (180.156g / mol) =

<h3>421g of glucose could be produced</h3>
7 0
3 years ago
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