$x^2+6x-7=0 \\ a=1 \\ b= 6 \\ c=-7 \\ \\ \boxed{\boxed{\Delta=b^2-4ac}} \\ \\ \Delta=6^2-4*1*(-7) \\ \Delta=36-(-28) \\ \Delta=64 \\ \Delta\ \textgreater \ 0 \Rightarrow \text{we have 2 solutions :} X_1 \ and X_2 \\ \\ \boxed{X_1= \frac{-b- \sqrt{\Delta} }{2a} } \Rightarrow X_1= \frac{-6-8}{2}=-7 \\ \\ \boxed{X_2= \frac{-b+ \sqrt{\Delta} }{2a} } \Rightarrow X_2= \frac{-6+8}{2} =1$

4 0

2 years ago

A die is rolled. The set of equally likely outcomes is {1, 2, 3, 4, 5, 6}. Find the probability of getting a 9.

mrs_skeptik [129]

Answer:

you are only rolling 1 dice the probability of getting 9 is 0 there are only 6 sides to one die

8 0

2 years ago

!!!!!!!!!! !!!!!!!!!!!!

jeyben [28]

Answer:

Step-by-step explanation:

6.5 * 24 = 156

Therefore B

4 0

2 years ago