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marysya [2.9K]
3 years ago
6

The probability that an archer hits a target on a given shot is .7 if five shots are fired find the probability that the archer

hits the target on three shots out of the five.
Mathematics
1 answer:
VikaD [51]3 years ago
5 0
This is a problem in "binomial probability."  Either the archer hits his target or he does not.  This experiment is performed 5 times (so that n=5), and the probability that the archer will hit the target is 0.7 (so that p=0.7).

We need to find the binomial probability that x=3 when the possible outcomes are {0, 1, 2, 3, 4, 5}.

You could use a table of binomial probabilities to evaluate the following:

P(5, 0.7, 3).

Alternatively, you could use a TI-83 or TI-84 calculator and its built-in "binompdf(  " function.

I evaluated binompdf(5,0.7,3) and obtained the result 0.309.


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After a storm, two street lights with the same length are leaning against each
Ray Of Light [21]

Answer:

c = 4.79 feet

Step-by-step explanation:

Given question is incomplete without a picture; find the question with the attachment.

Two poles AD and DB of same length are leaning against each other.

Distance between the poles (AB) = 45 feet

m(∠ADB) = 180°- (60 + 50)°

               = 70°

By sine rule,

\frac{sin50}{AD}=\frac{sin70}{45}=\frac{sin60}{DB}

AD=\frac{45\times (sin50)}{sin70}

      = 36.68 ft

Similarly,

DB = \frac{45\times sin60}{sin70}

     = 41.47 ft

Now c = DB - AD

           = 41.47 - 36.68

           = 4.79 feet

4 0
3 years ago
I need help solving number 11 please.
Mnenie [13.5K]

set up the triangle with the information given. then just solve for x.

3 0
3 years ago
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8090 [49]

help

okay so first add help the subtract help help finally dividing the help^2 equally help/help

3 0
3 years ago
Read 2 more answers
Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. He pla
krek1111 [17]
<span>B. It must be the same as when he constructed the arc centered at point A. This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined. Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing. "... places his compass on point B ..." Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense. A .It must be wider than when he constructed the arc centered at point A. Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer. B It must be the same as when he constructed the arc centered at point A. Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer. C. It must be equal to BQ. Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong. D.It must be equal to AB. Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
8 0
3 years ago
Read 2 more answers
Find the quotient. (12x 2 - 13x - 4) ÷ (4x + 1)
user100 [1]

Answer:

3x-4

Step-by-step explanation:

(12x^2-13x-4)\div(4x+1)= \\\\(3x-4)(4x+1)\div (4x+1)= \\\\3x-4

Hope this helps!

8 0
3 years ago
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