How to solve -7(x-1)^2-2 vertex form to standard form
1 answer:
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Answer:
option b
1 , 16, 121 , 13456
Step-by-step explanation:
Given in the question a function, f(x) = (x - 5)²
initial value = 4
First iteration
f(x0) = f(4) = (4 - 5)² = (-1)² = 1
x1 = 1
Second iteration
f(x1) = f(1) = (1 - 5)² = (-4)² = 16
x2 = 16
Third iteration
f(x2) = f(16) = ( 16 - 5)² = (11)² = 121
x3 = 121
Fourth iteration
f(x3) = f(121) = (121 - 5)² = (116)² = 13456
x4 = 13456
Given:
For a function f, .
To find:
The coordinates of a point on the graph of f.
Solution:
We have,
It means the value of function f is 10 at -4.
On a coordinate plane x-axis represents the input values and y-axis represents the output values of a function. So,
x-coordinate = input value = -4
y-coordinate = output value = 10
Therefore, the required coordinates of a point on the graph of f are (-4,10).