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wlad13 [49]
3 years ago
12

How to solve -7(x-1)^2-2 vertex form to standard form

Mathematics
1 answer:
ahrayia [7]3 years ago
4 0
Expand it

-7(x-1)^2-2
-7(x^2-2x+1)-2
-7x^2+14x-7-2
-7x^2+14x-9 is standard form
<span />
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Please help me on this
Readme [11.4K]

For this case we have to define root properties:

\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a

In addition, we know that:

a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}

On the other hand:

4 ^ 2 = 16

Thus, we can rewrite the given expression as:

\sqrt {4 ^ 2 * a ^ 8 * \frac {1} {b ^ 2}} =\\4 ^ {\frac {2} {2}} * a ^ {\frac {8} {2}} * \frac {1} {b ^ {\frac {2} {2}}} =\\4 * a ^ 4 * \frac {1} {b}

ANswer:

Option B

3 0
3 years ago
If the domain of the square root function f(x) is x
soldier1979 [14.2K]
<span>This question, in my opinion, is not well stated. If f(x) = √x, as the question statement seems to say, then the domain is not x<7. Rather, the domain is x≥0. If f(x) is not the square root function, but say f(x) = √(7-x) then the domain is x≤7, and for this function then the appropriate answer is d), since the x-term inside the radical has a negative coefficient.</span>
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3 years ago
Construct a triangle ABC in which BC-8 cm, B = 45° and AB-AC-3.5cm​
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Step-by-step explanation:

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What is the slope of the line that passes through (-1,3) and (4,6)
WINSTONCH [101]
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5 0
3 years ago
Ok whoever answers this correct will get 100 brainly points
Snezhnost [94]

Answer:

We are given an area and three different widths and we need to determine the corresponding length and perimeter.  

The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards.  This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.

The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards.  This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.

The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10.  This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.

Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.

<u><em>Hope this helps!</em></u>

3 0
2 years ago
Read 2 more answers
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