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3 years ago

A restaurant sold 8 times as many salads as they sold steaks. if they sold 4 steaks, how many salads did they sell?

1 answer:

7 0

32. For every one salad it was 8 steaks, so if they sold 4 steaks, just multiply 4 by 8, where 8 represents the number of salads for every steak. The answer would be 32. Correct me if I'm wrong but that my answer.

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Can somebody please help me with this question I need help ASAP

Alenkasestr [34]

The doctor would have 72 patients each week. Meaning 3744 each year.

3 0

3 years ago

Read 2 more answers

The school café charges $3 for hot lunch. This amount is automatically withdrawn from a student's lunch account each day they pu

Alexandra [31]

Answer:

15 dollars

Step-by-step explanation:

you do 3 × 5 which will give you 15

7 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

3 years ago

Product of two integers is -6 and There sum is 1

dedylja [7]

Answer:

3 and -2

Step-by-step explanation:

xy = -6

x + y = 1

let 'x' = y-1

y(y-1) = -6

y² - y + 6 = 0

(y-3)(y+2) = 0

y = 3 and -2

7 0

3 years ago

HURRY I'LL PICK A BRAINLIEST PERSON!!!

Nesterboy [21]

I would say the answer is B. Best of luck

3 0

3 years ago