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Salsk061 [2.6K]

3 years ago

12

Julia has three quarts, three nickles, and three pennies. How much money does she have?

1 answer:

Bogdan [553]3 years ago

8 0

Three quarters is $0.75 three nickels is $0.15 and three pennies is $0.03 add those together and you get $0.93

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The equation below describes a proportional relationship between x and y. What is the constant of? proportionality? y equals thr

lilavasa [31]

Answer:

The given equation is

y = $\frac{3}{7}$ x

→ $\frac{y}{x} = \frac{3}{7}$

reciprocating both sides, we get

→ $\frac{x}{y} = \frac{7}{3}$ ............(1)

→ Here x and y are Directly proportional to each other.

which means ,

→ x = k y , where k is constant of proportionality.

Or , $\frac{x}{y}$ = k ............................(2)

Equating (1) and (2),

k = $\frac {7}{3}$

5 0

3 years ago

If sinx = p and cosx = 4, work out the following forms :<br><br><br>

Kay [80]

Answer:

$\frac{p^2 - 16} {4p^2 + 16}$

Step-by-step explanation:

I will work with radians.

$\frac {\cos^2 \left(\frac{\pi}{2}-x \right)+\sin(-x)-\sin^2 \left(\frac{\pi}{2}-x \right)+\cos \left(\frac{\pi}{2}-x \right)} {[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)]}$

First, I will deal with the numerator

$\cos^2 \left(\frac{\pi}{2}-x \right)+\sin(-x)-\sin^2 \left(\frac{\pi}{2}-x \right)+\cos \left(\frac{\pi}{2}-x \right)$

Consider the following trigonometric identities:

$\boxed{\cos\left(\frac{\pi}{2}-x \right)=\sin(x)}$

$\boxed{\sin\left(\frac{\pi}{2}-x \right)=\cos(x)}$

$\boxed{\sin(-x)=-\sin(x)}$

$\boxed{\cos(-x)=\cos(x)}$

Therefore, the numerator will be

$\sin^2(x)-\sin(x)-\cos^2(x)+\sin(x) \implies \sin^2(x)- \cos^2(x)$

Once

$\sin(x)=p$

$\cos(x)=4$

$\sin^2(x)-\cos^2(x) \implies p^2-4^2 \implies \boxed{p^2-16}$

Now let's deal with the numerator

$[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)]$

Using the sum and difference identities:

$\boxed{\sin(a \pm b)=\sin(a) \cos(b) \pm \cos(a)\sin(b)}$

$\boxed{\cos(a \pm b)=\cos(a) \cos(b) \mp \sin(a)\sin(b)}$

$\sin(\pi -x) = \sin(x)$

$\sin(2\pi +x)=\sin(x)$

$\cos(2\pi-x)=\cos(x)$

Therefore,

$[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)] \implies [\sin(x)+\cos(x)] \cdot [\sin(x)\cos(x)]$

$\implies [p+4] \cdot [p \cdot 4]=4p^2+16p$

The final expression will be

$\frac{p^2 - 16} {4p^2 + 16}$

8 0

3 years ago

A recipe for a batch of cookies calls for 2 1/3 cups of flour for 24 cookies. Manuel wants to make 72 cookies. How many cups of

Fiesta28 [93]

He needs seven cups to make 72 cookies.

3 0

4 years ago

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What is the ratio of 14 by 8 1/2 when the answer says _ to 1?

bearhunter [10]

Zdnxfjncgfgnxfgnxfgnbfxgfnxdfngnxf

5 0

3 years ago

HELP PLEASE 77 POINTS

Brums [2.3K]

Answer:

You find it by finding the dimensions of the X up and down, and Y left and right

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers