6,384 meters in millimeters
2 answers:
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Answer:
The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.
Step-by-step explanation:
Given:
Maximum safe-weight of 37 cars = 82 tons
∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)
Mean weight of 1 car (μ) = 2 tons
Standard deviation of 37 cars = 0.8 tons
So, standard deviation of 1 car is given as:
Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?
The sample is normally distributed (Assume)
Now, let us determine the z-score of the mean weight.
The z-score is given as:
Now, finding P(x > 2.22) is same as finding P(z > 1.69).
From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.
But we need the area under the curve for z > 1.69.
So, we subtract from the total area. Total area is 1 or 100%.
So,
Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.
The GCF of 18 and 36 is 18. To solve this, use the picture attached. After creating the boxes, find a number that both 18 and 36 can be divided by, for example, 9. Now that you have 9, divide both 18 and 36 by 9. That equals 2 and 4. Place the numbers underneath the boxes you made previously and find another number that both 2 and 4 are divisible by. 2 and 4 are both able to be divided into 2. Do 2 divided by 2 and 4 divided by 2. Now you have the numbers 1 and 2. There aren't any numbers that can be divided into 1 and 2, so now you are left with the numbers 9 and 2. Multiply the numbers together to get a GCF of 18. Hope this helped!
Answer:
See the attachment below.
Step-by-step explanation:
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