All categories

3 years ago

An spple orchard sells apples in bags of 10.the orchard sold a total of 2,430 apples one day how many bags of apples was this

Mathematics

2 answers:

Virty [35]3 years ago

3 0

A bag holds 10 apples. The orchard sells 2430 apples in all. Divide the total by the part

2430/10 = 243

243 bags were used and sold.

hope this helps

mina [271]3 years ago

3 0

All we have to do is divide 2,439 by 10

2,439 ÷ 10 = 243

Let’s check our work by multiplying 243 by 10

243 x 10 = 2,439

Therefore the apple orchard sold 243 bags of apples

Hope this helps

You might be interested in

An astronaut who weighed 150 pounds on Earth found that his weight on Jupiter was 400 pounds. He captured an alien that weighed

Andrews [41]

The alien would be about 20 LBS on the earth

3 0

3 years ago

Which equation dose not represent a linear function of X

Naya [18.7K]

Answer:

Step-by-step explanation:

whenever you see this ^ you now it's not linear equation

8 0

3 years ago

Evaluate the expression 3.14(a2 + ab) when a = 3 and b = 4. (Input decimals only, such as 12.71, as the answer.)

soldier1979 [14.2K]

A= 3
b= 4

=3.14(a^2 + ab)
substitute the given a & b values in expression

=3.14((3)^2 + (3*4))
multiply inside parentheses

=3.14(9 + 12)
add inside parentheses

=3.14(21)
multiply

=65.94

ANSWER: 65.94

Hope this helps! :)

8 0

2 years ago

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

6 0

2 years ago

What is the sum of V-2 and V-18?

Rufina [12.5K]

Answer:

$\sqrt{ - 2} + \sqrt{ - 18} \\ = \sqrt{2} i + \sqrt{ - 2} \sqrt{9} \\ = \sqrt{2} i + 3\sqrt{2} i \\ = 4\sqrt{2} i$

4 0

2 years ago