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kodGreya [7K]
3 years ago
15

please help me! Bethany incorrectly simplified the following expression: (4 x 10^11) (3 x 10^-14) + 0.000005 Which of Bethany’s

steps show an error based solely on her previous step? Choose all that apply: A. Step one: (4 x 10^11) (3 x 10^-14) + (5 x 10^-5) B. Step two: (12 x 10^-3) + (5 x 10^-5) C. Step three: (120 x 10^-4) + (5 x 10^-5) D. Step four: (120 x 10^-4) + (50 x 10^-4) E. Step five: 170 x 10^-8 F. Step six: 1.7 x 10^-6
Mathematics
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

Below.

Step-by-step explanation:

Step 1:  it is  5  x 10^-6 not 5 x 10^-5.

Step 5 : the result of the addition is 170 x 10^-4 not 170 x 10^-8.

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Caroline scored 8 more points than three times the number of points as Kamila. If Kamila scores 8 points in her next try, she wi
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Answer: 32

step by step explanation: 40 - 8 = 32

8 0
2 years ago
george completed 3/5th of work in 9 days with the help of paul he completes remaining work in 4 days.In how many days paul alone
IRINA_888 [86]
If George completed 3/5 of work in 9 days, it means that he needs 3 days to finish 1/5th of the work.

The remaining part is 2/5 because 1-3/5=2/5. 2/5 is also 6/15

From this, how much did George do? in the first 3 days he did 1/5th and then one more day was left, during which he did 1/5/3=1/15th.

So he did in total 1/15+1/5=1/15+3/15=4/15.
this means that Paul did the rest of 6/15, so Paul did 6/15-4/15=2/15.

So we know that he does 2/15 in 4 days, which means that every two days he can do 1/15 of the work

so he would need 15 times 2 days to finish the work - 30 days!
6 0
3 years ago
A theater has 56 rows of seats. If there are 13 seats in the first row, 18 in the 2nd row, 23 in the 3rd row. How many seats are
Anna35 [415]

Answer:

8428

Step-by-step explanation:

According to the Question,

  • Given, A theater has 56 rows of seats. If there are 13 seats in the first row, 18 in the 2nd row, 23 in the 3rd row.

We have a number sequence  13, 18, 23, ...

  • We can say that this is an arithmetic sequence because of the common difference 'd', is equal to 5, and the first term 'a1' is equal to 13.
  • The formula for the sum of an arithmetic sequence with n terms is given is S_n= \frac{n}{2} [2a_1+(n-1)d]S .

Substitute the given values into the equation to solve for the sum of the 56 rows of seats.

S_56= \frac{56}{2}[2(13)+(56-1)(5)]\\S_{56}=28\left[26+275\right]\\S_{56}=28\left[301\right]\\S_{56}=8428

Therefore, there are 8428 seats in all.

4 0
3 years ago
Jack Frost was decorating the car windows in the teacher’s parking lot. He puts 2 snowflakes on each of the four windows of the
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Answer: He can completely decorate 11 cars

Explanation: since he puts 2 snowflakes on each of the 4 windows on one car, in total Jack uses 8 snowflakes per car. If he makes 90 snowflakes, 90 divided by 8 gives you the amount of cars he can decorate. 90/8 = 11.25, but since you can’t have .25 cars the answer is 11.
3 0
2 years ago
Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
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