Question

The first three terms of a sequence are given. Round to the nearest thousandth (ifnecessary).3 33,2'4'Find the 8th term

Answer 1

You can notice that each term of the sequence has a denominator with powers of 2. The first term has 2 powered to 0, the second term has a 2 powered to 1 and so on. The numerator is always 3.

Then, for the n-th term, you have:

$a_n=\frac{3}{2^{n-1}}$