2 years ago

The first three terms of a sequence are given. Round to the nearest thousandth (ifnecessary).3 33,2'4'Find the 8th term

1 answer:

4 0

You can notice that each term of the sequence has a denominator with powers of 2. The first term has 2 powered to 0, the second term has a 2 powered to 1 and so on. The numerator is always 3.

Then, for the n-th term, you have:

$a_n=\frac{3}{2^{n-1}}$

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