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3 years ago

Given f(x)=x^3 and g(x)= 1-5x^2

Mathematics

1 answer:

Allisa [31]3 years ago

3 0

Im doing this for points lol

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The diagram shows a solid metal cuboid.

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3 years ago

How many ounces of each kind of food should be used?

riadik2000 [5.3K]

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3 years ago

I WILL MARK BRAINLIEST

Reil [10]

Answer:

Step-by-step explanation:

The students in social studies club is bias, the boys will probibly pick the easier one and the teachers will pick the one that causes less mess. but the only way to have a fair and random survey is to ask every student.

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3 years ago

Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

4 0

4 years ago

Write the equation (1,2) in a point-slope form.

Bogdan [553]

y-2= m(x-2)

Step-by-step explanation:

Y-y1=m(x-x1)

it's just plugging in the points to point slope formal

3 0

4 years ago

Read 2 more answers