Question

Greg is designing a clock face. Using the center of the clock face as the origin, he keeps its diameter at 10 units. Match the positions of the hours on the clock face to their corresponding coordinates. Tiles 3 o'clock (0, -5) 6 o'clock (5, 0) 9 o'clock (0, 5) 12 o'clock (-5, 0) Pairs arrowBoth arrowBoth arrowBoth arrowBoth

Answer 1

3o'clock - directly to the right of the origin; on the x axis - (5,0)
6o'clock - directly below the origin; on the y-axis - (0,-5)
9o'clock - directly to the left of the origin; on the x-axis, (-5,0)
12o'clock - directly above the origin; on the y-axis, - (5,0)

Answer 2

Answer:

Given: Center of the clock face is at origin that is ( 0 , 0 )

To find : Position of the hours on the clock faces 3 o'clock , 6 o'clock , 9

o'clock and 12 o'clock.

We know that 3 o'clock on watch is on the straight right side of the center.

So, here 3 o'clock lies on right side of x-axis or positive side of x-axis.

Coordinate of 3 o'clock = ( 5 , 0 )

We know that 6 o'clock on watch is on straight bottom of the center.

So, here 6 o'clock lies on downside of y-axis or negative side of y-axis.

Coordinate of 6 o'clock = ( 0 , -5 )

We know that 9 o'clock on watch is on the straight left side of the center.

So, here 9 o'clock lies on left side of x-axis or negative side of x-axis.

Coordinate of 9 o'clock = ( -5 , 0 )

We know that 12 o'clock on watch is on the straight upside of the center.

So, here 12 o'clock lies on upside of y-axis or positive side of y-axis.

Coordinate of 12 o'clock = ( 0 , 5 )