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Mademuasel [1]
3 years ago
13

Question in photo (:

Mathematics
1 answer:
Alenkasestr [34]3 years ago
6 0
Answer equals c === 33
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It’s my final Test please help
satela [25.4K]
The correct answer is A :)
8 0
3 years ago
3 eggs and 2 cups of sugar to make 30 cookies. How many eggs and cups of sugar do you need to make 50 cookies.
sineoko [7]

Answer:

<u>5 eggs and 3.33 cups of sugar</u>

Step-by-step explanation:

3 eggs are required to make 30 cookies

1 cookie needs 3/30 eggs

so,50 cookies needs 50*3/30=150/30=<u>5 eggs</u>

2 cups of sugar is required to make 30 cookies

1 cookie needs 2/30 cups of sugar

so,50 cookies needs 50*2/30=100/30=<u>3.33 cups of sugar</u>

5 0
3 years ago
58-(1/4)2 i dont get how to solve this
xeze [42]

Answer:

57.5

Step-by-step explanation:

First you would have to multiply following PEMDAS so

(1/4)(2)

=0.5

Then subtract 58 and 0.5

58-0.5

=57.5

and thats your answer

5 0
3 years ago
Read 2 more answers
In imaginary numbers can you multiply two radicals that have negative values under them that do not square to whole numbers
ElenaW [278]
Yes, you can; based on the inherent assumption that the "two radicals that have negative values" are, in fact, "imaginary numbers" .

Take, for example, the commonly known "imaginary number":  "i" ;  which represents the "imaginary number" ;  " √-1 " .

Since:  "i = √-1" ; 

Note that:   " i² = (√-1)² = √-1 * √-1 = √(-1*-1) = √1 = 1 .
__________________________________________________
7 0
4 years ago
Read 2 more answers
A car is driving away from a crosswalk. The formula d = t2 + 2t expresses the car's distance from the crosswalk in feet, d, in t
alukav5142 [94]

Answer:

8 feet per second.

Step-by-step explanation:

We have been given that a car is driving away from a crosswalk. The formula d=t^2+2t expresses the car's distance from the crosswalk in feet, d, in terms of the number of seconds, t, since the car started moving.

We will use average change formula to solve our given problem.

\text{Average change}=\frac{f(b)-f(a)}{b-a}

\text{Average change}=\frac{d(5)-d(1)}{5-1}

\text{Average change}=\frac{(5)^2+2(5)-((1)^2+2(1))}{4}

\text{Average change}=\frac{25+10-(1+2)}{4}

\text{Average change}=\frac{35-3}{4}\\\\\text{Average change}=\frac{32}{4}\\\\\text{Average change}=8

Therefore, the the car's average speed over the given interval of time would be 8 feet per second.

8 0
3 years ago
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