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OverLord2011 [107]
3 years ago
5

On a coordinate plane, 4 lines are shown. Line A B goes through (negative 4, 3) and (4, 3). Line C D goes through (negative 3, 0

) and (3, 2). Line F G goes through (negative 3, negative 1) and (3, negative 3). Line H J goes through (negative 1, negative 4) and (1, 2). Which of the lines that appear in the graph would be parallel to a line with a slope of 3 and a y-intercept at (0, 3)?
Mathematics
2 answers:
MAVERICK [17]3 years ago
8 0
The line is HJ
Step-by-step explanation:
we know that
The formula to calculate the slope between two points is equal to

step 1
Find the slope line AB
we have
A(-4,-2),B(4,2)
substitute the values in the formula



step 2
Find the slope line CD
we have
C(-4,0),D(4,-4)
substitute the values in the formula



step 3
Find the slope line FG
we have
F(-3,-3),G(0,3)
substitute the values in the formula



step 4
Find the slope line HJ
we have
H(-1,3),J(1,-1)
substitute the values in the formula



step 5
Compare the slopes
we have




we know that
If two lines are perpendicular, then their slopes are opposite reciprocal
so
The slope of a line perpendicular to a line that has a slope of One-half must be negative 2
therefore
The line is HJ
kondor19780726 [428]3 years ago
5 0

Answer:

The awnser is Line HJ.

Step-by-step explanation:

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Step-by-step explanation:

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Inverse Functions

One-to-one

Suppose f : A ⇥ B is a function. We call f one-to-one if every distinct

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There is a way of phrasing the previous definition in a more mathematical

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Example. f : R ⇥ R where f(x) = x2 is not one-to-one because 3 ⌅= 3

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Horizontal line test

If a horizontal line intersects the graph of f(x) in more than one point,

then f(x) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate – for example, (2, 3) and

(4, 3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two dierent objects in the domain to the same object

of the target.

If every horizontal line in R2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : R ⇥ R where f(x) = x2. There is a

horizontal line that intersects this graph in more than one point, so f is not

one-to-one.

66

Inverse Functions

One-to-one

Suppose f : A —* B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c e A with

a ~ c, we are guaranteed that f(a) $ f(c).

Example. f : IR —* JR where f(x) = x2 is not one-to-one because 3 ~ —3

and yet f(3) = f(—3) since f(3) and f(—3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(.x) in more than one point,

then f(z) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate — for example, (2,3) and

(4,3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two different objects in the domain to the same object

of the target.

If every horizontal line in JR2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : JR —, R where f(z) = z2. There is a

horizontal line that intersects this h in more than one point, so f is not

Step-by-step explanation:

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