Answer:
a. 3,392.7 N
b. 3,392.7 N
Explanation:
We are given the following information;
- Mass of the truck as 1052 kg
- initial speed as 0 m/s
- Final speed as 20.0 m/s
- Time taken as 6.20 s
#a. We are required to calculate the acceleration;
We need to know the formula of getting acceleration;
a = (v-u)/t
Where v is the final velocity, u is the initial velocity
Therefore;
a = (20 m/s - 0 m/s)/6.20s
= 3.225 m/s²
Thus, the average acceleration of the truck is 3.225 m/s²
#b. We are required to calculate the net force on the truck
We need to know that;
According to the second Newton's law of motion, F=ma
Where F is the net force, m is the mass and a is the acceleration.
Therefore;
Net force, F = mass × Acceleration
= 1052 kg × 3.225 m/s²
= 3,392.7 N
Thus, the net force on the truck is 3,392.7 N
I am pretty sure that non of the listed options above is correct. Current
, resistance, potential difference and induction all don't have the dimension of an energy that d<span>ifference in electrical potential energy should have. Quite a tricky question, be careful.</span>
Answer:
2.11 %
Explanation:
In acidic medium iron is in Fe ⁺³ oxidation state .
Equivalent weight = 56 / 3
= 18.33 gm
acid used in titration
= 16.37 mL of .0233 M
= 16.37 x .0233 mL of M soln
= .38 mL of M soln
.38 mL of M soln reacts with .3298 gm of ore
1000 mL of M soln = (.3298 / .38) x 1000 gm of iron ore
867.89 gm
This must contain one gm equivalent of iron
or 18.33 gm
867.89 gm of ore contains 18.33 gm of iron
mass % of iron in the given ore
= (18.33 / 867.89) x 100
= 2.11 %
Answer:
Distance, d = 99990 meters
Explanation:
It is given that,
Speed of the train, v = 200 km/h = 55.55 m/s
Time taken, t = 1800 s
Let d is the distance covered by the train. We know that the speed of an object is given by total distance covered divided by total time taken. Mathematically, it is given by :



d = 99990 m
So, the distance covered by the train is 99990 meters. Hence, this is the required solution.