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svetoff [14.1K]
2 years ago
15

Two electrodes (0.68 mm apart) in your car's spark plug are subject to a 3.5 kV potential difference. What magnitude electric fi

eld does this produce in the region between the two electrodes
Physics
1 answer:
Lubov Fominskaja [6]2 years ago
3 0

The magnitude of the electric field produced in the region between the two electrodes is 5.15 \times 10^6 \ V/m.

<h3>Electric field strength</h3>

The electric field strength produced in the region between the two electrodes is calculated as follows;

E = \frac{v}{d}

where;

  • v is the potential difference = 3.5 kV = 3,500 V
  • d is the separation distance = 0.68 mm

The electric field strength is calculated as follows;

E = \frac{3500}{0.68 \times 10^{-3}} \\\\E = 5.15 \times 10^6 \ V/m

Thus, the magnitude of the electric field produced in the region between the two electrodes is 5.15 \times 10^6 \ V/m.

Learn more about electric field here: brainly.com/question/14372859

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A couple of astronauts agree to rendezvous in space after hours. Their plan is to let gravity bring them together. She has a mas
Oduvanchick [21]

Answer:

(a) Acceleration of female astronaut = 9.33*10^-12 m/s^2; Acceleration of male astronaut = 7.56*10^-12 m/s^2

(b) 27.013 days

(c) No, their accelerations would not be constant.

Explanation:

In the given question, we have:

Mass of female astronaut M_{1} = 60.0 kg

Mass of male astronaut M_{2} = 74.0 kg

Distance between them (S) = 23.0 m

(a) The free-body diagram is shown in the attached figure.

Using the equations below, the initial accelerations of the two astronauts can be calculated:

Force of gravity (F) = \frac{G*M_{1}*M_{2}}{S^{2} }

G = 6.67*10^-11 \frac{m^{3} }{kg*s^{2} }

F = (6.67*10^-11 *60*74)/23^2 = 5.598*10^-10 N

For the female astronaut, her initial acceleration = F/M_{1} = 5.598*10^-10/60 = 9.33*10^-12 m/s^2

For the male astronaut, his acceleration = F/M_{2} = 5.598*10^-10/74 = 7.56*10^-12 m/s^2

(b) Since the different between their mass is not much, we can deduce that:

a_{average} = \frac{a_{1}+a_{2}}{2} = (9.33*10^-12 + 7.56*10^-12)/2 = 8.445*10^-12 m/s^2

Using the equation below, we can calculate the the time:

S = ut + 1/2 (at^2)   where u = 0

23 = 1/2 (8.445*10^-12)*t^2

t^2 = 5.447*10^12

t = 2333883.044 s = 27.013 days

(c) No, their accelerations will not be constant. It will increase because their radii would be decreasing.

8 0
3 years ago
Which two phrases describe critical thinking skills used in the pursuit of<br> science?
SSSSS [86.1K]

Answer:

A. Expanding personal knowledge by reading articles from scientific

journals

B. Analyzing the different parts of a physical phenomenon to see

how they fit together

C. Predicting the impact that answering an important scientific

question would have on people

D. Developing a question that can be answered through testing or

observation

E. Developing logical arguments for providing incentives for

scientific research

6 0
3 years ago
The thing that is circled, correct me if im wrong please.
Irina18 [472]
It looks correct, but that graph only shows position and time?
5 0
3 years ago
Read 2 more answers
Imagine you use Nitrogen as your gas. If you have the cold side as cold as you can without liquefying it (78 K), and run the hot
alina1380 [7]

Answer:

The efficiency of a Stirling engine is 74%

Explanation:

Given:

Temperature of gas when it is cold T_{1} = 78 K

Temperature of gas when it is hot T_{2} = 300 K

The efficiency of a stirling engine,

  \eta =1 - \frac{T_{1} }{T_{2} }

  \eta = 1- \frac{78}{300}

  \eta = 1-0.26

  \eta = 0.74

∴ \eta = 74 \%

Therefore, the efficiency of a Stirling engine is 74%

5 0
3 years ago
Part of understanding the physical effects on Mars, we must understand
Ber [7]

Answer:

so easy add the subtract then multiplay the add

Explanation:

8 0
3 years ago
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