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padilas [110]
3 years ago
10

Calculate the volume in liters of a M magnesium fluoride solution that contains of magnesium fluoride . Round your answer to sig

nificant digits.
Chemistry
1 answer:
AveGali [126]3 years ago
8 0

The given question is incomplete. the complete question is:

Calculate the volume in liters of a 0.91 M magnesium fluoride solution that contains 249.2 g of magnesium fluoride . Round your answer to 2 significant digits.

Answer: 4.4 Liters

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{249.2g}{62.3g/mol}=4.00moles

V_s =volume of solution in L

0.91=\frac{4.00}{V_s}

Thus the volume in liters is 4.4 L

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The SA node, the cardiac center in the medulla oblongata, and the endocrine system
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3 years ago
Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802
Anvisha [2.4K]

Answer:

1 gramo de metano aporta 50.125 kilojoules.

1 gramo de metano aporta 48.246 kilojoules.

Explanation:

La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo (Q), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto (\bar {Q}), en kilojoules por mol, dividido por su masa molar (M), en gramos por mol:

Q = \frac{\bar Q}{M} (1)

A continuación, analizamos cada caso:

Metano

Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }

Q = 50.125\,\frac{kJ}{g}

1 gramo de metano aporta 50.125 kilojoules.

Octano

Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }

Q = 48.246\,\frac{kJ}{mol}

1 gramo de metano aporta 48.246 kilojoules.

3 0
2 years ago
Discuss the shapes of s- orbitals, p-orbitals and d-orbitals.
timurjin [86]

The azimuthal quantum number (l) determines its orbital angular momentum and describes the shape of the orbital.

s-orbitals (for example 1s, 2s) are spherically symmetric around the nucleus of the atom.

p-orbitals are dumb-bell shaped. l = 0,1...n-1, when l = 1, that is p subshell.

d-orbitals are butterfly shaped.

3 0
3 years ago
What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n =
Lady bird [3.3K]

Answer:

4.86\times10^{-7}\ \text{m}

Explanation:

R = Rydberg constant = 1.09677583\times 10^7\ \text{m}^{-1}

n_1 = Principal quantum number of an energy level = 2

n_2 = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}

The wavelength of the light emitted is 4.86\times10^{-7}\ \text{m}.

6 0
3 years ago
What is the splitting of the signal in the 1H NMR spectrum for the methyl protons of 1-bromo-2-methylpropane?
Arada [10]

Answer:

doublet

Explanation:

Proton MNR is used for the determination of no. of equivalents protons in a molecule

In the molecule, single NMR signal is produced for each set of protons.

Signal splitting is called spin-spin coupling and the splitting of signals depends upon the no. of neighboring proton.

The no. of signal for a proton is equal to n+1, where n is neighboring protons.

In 1-bromo-2-methylpropane, neighboring proton for both methyl protons are one. But the chemical environment of both the methyl protons are different.

Neighboring proton for methyl protons = 1

No. of signal for methyl protons = 1+1 =2

Hence, two doublets will be generated for each set of methyl protons. protons.

3 0
3 years ago
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