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padilas [110]
3 years ago
10

Calculate the volume in liters of a M magnesium fluoride solution that contains of magnesium fluoride . Round your answer to sig

nificant digits.
Chemistry
1 answer:
AveGali [126]3 years ago
8 0

The given question is incomplete. the complete question is:

Calculate the volume in liters of a 0.91 M magnesium fluoride solution that contains 249.2 g of magnesium fluoride . Round your answer to 2 significant digits.

Answer: 4.4 Liters

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{249.2g}{62.3g/mol}=4.00moles

V_s =volume of solution in L

0.91=\frac{4.00}{V_s}

Thus the volume in liters is 4.4 L

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Boyle's law p1V1=p2V2 

p2=(p1V1)/V2

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8 0
3 years ago
Consider the reaction of peroxydisulfate ion (S2O2−8) with iodide ion (I−) in aqueous solution: S2O2−8(aq)+3I−(aq)→2SO2−4(aq)+I−
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Answer:

r = 3.61x10^{-6} M/s

Explanation:

The rate of disappearance (r) is given by the multiplication of the concentrations of the reagents, each one raised of the coefficient of the reaction.

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\frac{2.6x10^{-6}}{3.9x10^{-6}} = (\frac{0.018}{0.027})^xx(\frac{0.036}{0.036})^y

0.67 = 0.67^x

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Now, to find the coefficient y let's do the same for the experiments 1 and 3:

\frac{r1}{r3} = \frac{0.018x0.036^y}{0.036x0.054^y}

\frac{2.6x10^{-6}}{7.8x10^{-6}} = (\frac{0.018}{0.036})x(\frac{0.036}{0.054})^y

0.33 = 0.5x 0.67^y

0.67 = 0.67^y

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Now, we need to calculate the constant k in whatever experiment. Using the first :

2.6x10^{-6} = kx0.018x0.036kx6.48x10^{-4} = 2.6x10^{-6}

k = 4.01x10^{-3} M^{-1}s^{-1}[/tex]

Using the data given,

r = 4.01x10^{-3}x1.8x10^{-2}x5.0x10^{-2}

r = 3.61x10^{-6} M/s

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3 years ago
What does osmosis depend on? A. the identity of the solute and solvent B. how much solvent is present in the solution C. the num
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Osmosis is a special kind of diffusion where solvent particles move through a semi permeable membrane from low concentration of solute to high concentration of solute.

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Describe the reason why a reaction between two substances comes to an end.
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Hope that was helpful.Thank you!!!

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Name any <br>three kinds of mixtures with example​
sleet_krkn [62]

Answer:

Here are a few more examples:

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Oxygen and water (Sea foam)

Petroleum, hydrocarbons, and fuel additives (Gasoline)

Heterogeneous mixtures possess different properties and compositions in various parts i.e. the properties are not uniform throughout the mixture.

Examples of Heterogeneous mixtures – air, oil, and water, etc.

Examples of Homogeneous mixtures – alloys, salt, and water, alcohol in water, etc.

Explanation:

8 0
2 years ago
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