Answer:
<em>1</em><em>.</em><em> </em><em>Element</em>
<em>2</em><em>.</em><em> </em><em>Heterogeneous</em><em> mixture</em>
<em>3</em><em>.</em><em> </em><em> </em><em>Compound</em>
<em>4</em><em>.</em><em> </em><em>Mixture</em><em> </em><em>or </em><em>Substances</em>
<em>5</em><em>.</em><em> </em><em>Elements</em>
<em>6</em><em>.</em><em> </em><em>Homogeneous</em><em> mixture</em>
Answer:
C = Electrons are won and lost.
Explanation:
The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining and losing the electrons and oxidation state of elements are changed.
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Consider the following reactions.
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O
The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.
H₂S + 2NaOH → Na₂S + 2H₂O
The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.
Oxidizing agents:
Oxidizing agents oxidize the other elements and itself gets reduced.
Reducing agents:
Reducing agents reduced the other element are it self gets oxidized.
Explanation :
Actually bromine have 35 electrons when it is neutral, and if the number of electrons is increased by 1 it gains a relative negative charge of 1.
Also written as : -1
Answer:
A. Hot water increases the collision rate of the molecules, causing the
reaction to occur faster.
Explanation:
Hot water molecules move faster than cold water molecules.
Answer:
T = 401.6 K
Explanation:
Given reaction:

The thermodynamic parameters; ΔG°, ΔH° and ΔS° are related via the Gibbs -Helmholtz equation given as:

For a given reaction, the gibbs free energy change ΔG° is related to the equilibrium constant K as:

It is given that K = 1,
Therefore,

Substituting for ΔG° in equation (1)


