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3 years ago

9

Melissa and Thomas both solved the same problem using different methods. Their work is shown below. Who solved the problem incor

recly? Explain.

1 answer:

MaRussiya [10]3 years ago

5 0

Pls show the problem so I can solve

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Convert these unlike fractions to equivalent like fractions and add them. You must use the lcd to get the answer correct. If pos

ra1l [238]

Unlike fraction 1/7 is converted to equivalent like fraction 2/14 and the sum of 2/14 + 3/14 = 5/14.

As given in the question,

Given fraction is equal to:

1/7=? + 3/14=?

Here there are two fractions

1/7 and 3/14

LCD( least common denominator) of 7 and 14 is equal to 14.

Now make them like fractions

1/7 is equivalent to

( 1/7) × ( 2/2) = 2/ 14

Now 2/14 and 3/14 are like fractions

Sum of like fractions is:

2/14 + 3/14

= ( 2+ 3) / 14

= 5/ 14

Therefore, the conversion of unlike fraction 1/7 to like fraction is 2/14. And sum of 2/14 + 3/14 = 5/14.

The complete question is:

Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If possible, reduce the final sum. 1/7=? + 3/14=?

Learn more about fractions here

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4 0

1 year ago

A new shopping mall records 120 total shoppers on their first day of business. Each day after that, the number of shoppers is 10

Iteru [2.4K]

Answer:

$1,139\ shoppers$

Step-by-step explanation:

we know that

In this problem we have a exponential function of the form

$y=a(b)^{x}$

where

a is the initial value or y-intercept

b is the base of the exponential function

r is the rate in decimal form

b=(1+r)

In this problem we have

x ----> the number of days

y ----> the number of shoppers

a=120

r=10%=10/100=0.10

b=1+0.10=1.10

substitute the values

$y=120(1.10)^{x}$

First day

$y=120$

Second day

For x=1 day

substitute the value of x in the equation and solve for y

$y=120(1.10)^{1}=132$

Third day

For x=2 days

$y=120(1.10)^{2}=145$

Fourth day

For x=3 days

$y=120(1.10)^{3}=160$

Fifth day

For x=4 days

$y=120(1.10)^{4}=176$

Sixth day

For x=5 days

$y=120(1.10)^{5}=193$

Seventh day

For x=6 days

$y=120(1.10)^{6}=213$

Adds the numbers

$120+132+145+160+176+193+213=1,139$

3 0

3 years ago

Read 2 more answers

anna, becky, christina, debbie, and esther are the five candidates for student representative for the school board. two students

Flauer [41]

Probability that he will choose debbie and esther as the two representatives is 1/20 .

<h3>What is the meaning of Probability ?</h3>

Probability is the stream in mathematics in which likeliness of an event to happen is studied.

The range of probability lies between 0 to 1 , where 0 indicates uncertainty and 1 indicates certainty.

It is given that anna, becky, christina, debbie, and esther are the five candidates for student representative for the school board.

two students will be selected, and they will alternate attending the school board meetings.

all five students are equally well qualified, so the school superintendent decides to draw names at random.

probability he will choose debbie and esther as the two representatives = ?

Probability of chosing debbie is 1/5

Probability of choosing Esther is also 1/5

Either of them if chosen first the probability is 1/5

and the either of them chosen second the probability is 1/4

Probability that he will choose debbie and esther as the two representatives = (1/5)*(1/4) = 1/20 .

To know more about Probability

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6 0

2 years ago

For each value of x, determine whether it is a solution to x+37 = 46. Is it a solution? X 6 ? х 12 x 9 x 83 ?

Paha777 [63]

1. If x=6, 6+37=?46 43≠46. It isn’t a solution.
2. If x=12, 12+37=?46 49≠46. it’s not a solution.
3. If x=9, 9+37=?46. 46=46. It’s a solution!
4. If x=83, 83+37=?46. 120≠46. Not a solution.

Only x=9 Is a solution.

Hope it helps!

6 0

2 years ago

Read 2 more answers

Order from greatest to least<br>.03 .0 .32. 07 .7<br>

4vir4ik [10]

Answer: .7, .32, .07, .03, .0

Step-by-step explanation:

6 0

3 years ago