The height of a triangle is 8cm more than the base. If the area is 90cm^2, find the base and the height
1 answer:
You might be interested in
Given:
The equation is:
It cuts the x-axis and y- axis at the point A and B respectively.
The area of ∆AOB =12 sq.units.
To find:
The value of <em>k</em>.
Solution:
We have,
Substituting to find the y-intercept.
Substituting to find the x-intercept.
Area of a triangle is:
The height of the ∆AOB is because distance cannot be negative and the base of the ∆AOB is
. So, the area of the ∆AOB is:
It is given that, the area of ∆AOB = 12 sq.units.
Therefore, the value of k is either 24 or -24.
Given :
▪︎Measure of ∠R = 90°
▪︎Segment OR = Segment RN
Which will mean, ∠O = ∠N.
Thus :
Which means :
Measure of ∠O = 45°
Measure of ∠N = 45°
Therefore, the measures of these angles in ascending order = 45,45,90.