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Orlov [11]
2 years ago
15

The height of a triangle is 8cm more than the base. If the area is 90cm^2, find the base and the height

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
3 0
I get the base to be 4.74 and the height to be 12.74
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Answer:

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Step-by-step explanation:

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The line 3x-8y=k cuts the x-axis and y- axis at the point A and B respectively. If the area of ∆AOB =12sq.units, find the value
Sladkaya [172]

Given:

The equation is:

3x-8y=k

It cuts the x-axis and y- axis at the point A and B respectively.

The area of ∆AOB =12 sq.units.

To find:

The value of <em>k</em>.

Solution:

We have,

3x-8y=k

Substituting x=0 to find the y-intercept.

3(0)-8y=k

0-8y=k

y=\dfrac{k}{-8}

y=-\dfrac{k}{8}

Substituting y=0 to find the x-intercept.

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3x-0=k

x=\dfrac{k}{3}

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A=\dfrac{1}{2}\times base\times height

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A=\dfrac{1}{2}\times \dfrac{k}{8}\times \dfrac{k}{3}

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It is given that, the area of ∆AOB = 12 sq.units.

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k=\pm \sqrt{576}

k=\pm 24

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RoseWind [281]

Given :

▪︎Measure of ∠R = 90°

▪︎Segment OR = Segment RN

Which will mean, ∠O = ∠N.

Thus :

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=\tt 90 + 2x = 180

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=\tt x =  \frac{90}{2}

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