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Blizzard [7]
3 years ago
14

Solve for X 5/8 = 15/x show work pls

Mathematics
1 answer:
taurus [48]3 years ago
4 0
<span>5 = 15
---------
8 =  x
cross multiply
5x =120
5x÷5 = 120÷5
x = 24

Check
5/8 = 15/24
.625 = .625
</span><span>
</span>
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Joey is saving up for a down payment on a car. He plans to invest $2,000 at the end of every year for 3 years. If the interest r
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A=Annual amount=2000
i=annual interest=0.0205
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5 0
3 years ago
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Which is bigger 2m or 275cm
aliina [53]

Answer:

275.

Step-by-step explanation:

If you convert 2m into CM you get 200.
If you convert 275 cm into M you get 2.75. So 275cm is bigger.

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2 years ago
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Which of the following sums would be under the radical symbol to find the distance between the points (7, -1) and (-8, -9)?
Alexxandr [17]

Sadly, you didn't put any sums on your list of choices. 
In fact, I can't even find a list of choices !

To find the distance between  (7, -1)  and  (-8, -9),
you would build a sum under a square-root (radical)
symbol, and it would look something like this:

               √ ( 225 + 64 ) .
 
5 0
3 years ago
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In a random sample of 45 newborn babies, what is the probability that 40% or fewer of the sample are boys. (Use 3 decimal places
erastova [34]

Answer:

z= \frac{p- \mu_p}{\sigma_p}

And the z score for 0.4 is

z = \frac{0.4-0.4}{\sigma_p} = 0

And then the probability desired would be:

P(p

Step-by-step explanation:

The normal approximation for this case is satisfied since the value for p is near to 0.5 and the sample size is large enough, and we have:

np = 45*0.4= 18 >10

n(1-p) = 45*0.6= 27 >10

For this case we can assume that the population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Where:

\mu_{p}= \hat p = 0.4

\sigma_p = \sqrt{\frac{p(1-p)}(n} =\sqrt{\frac{0.4(1-0.4)}(45}= 0.0703

And we want to find this probability:

P(p

And we can use the z score formula given by:

z= \frac{p- \mu_p}{\sigma_p}

And the z score for 0.4 is

z = \frac{0.4-0.4}{\sigma_p} = 0

And then the probability desired would be:

P(p

7 0
3 years ago
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Consider the problem of distributing 10 distinct books among three different people with each person getting at least one book.
kakasveta [241]

The strategy used is not well, because it becomes very complex and very difficult to calculate the ways, it would play one by one, that is, despite making sense, the last part of the way to distribute the books how is it obtained? why would it be like this?

There is a much more effective way of solving the problem, and that is to divide it by cases.

Case 1:

Choose four books from the 10 available books and give them to the first student

Then choose three books from the remaining six books and give them to the second student.

Finally, give the remaining three books to the last student

Case 2:

Choose three books from the 10 available books and give them to the first student

Then choose four books from the remaining seven books and give them to the second student.

Finally, give the remaining three books to the last student

Case 3:

Choose three books from the 10 available books and give them to the first student

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Lastly, give the remaining four books to the last student

First it is to calculate the number number in each case by means of combinations, multiply the options per case and then add the final value in each case.

6 0
3 years ago
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