1: (-3)2= -6
2: (-6)4= -24
3: (-1)8= -8
The only equation that works with x=-6 is A
Answer:
A. 2 distinct roots.
Step-by-step explanation:
2x^2 + 8x + 3 = 0
Finding the discriminant:
b^2 - 4ac = 8^2 - 4 * 2 * 3
= 64 - 24
= 40
The discriminant is positive but not a perfect square
So there are 2 distinct ,real, irrational roots.
To factor the given function, find a term that is divisible by both terms. For this problem, the factor would be 2, since 2x^2 and -18 are both divisible by 2.
2(x^2 - 9)
You could further factor out x^2 - 9 because it is factorable by (x - 3) and (x + 3). Thus, it would be
2(x -3)(x+3)