Answer:
Hence, the perimeter of the triangles are:
P=123.2727 dm
P'=102.7272 dm
Step-by-step explanation:
In two similar triangles:
The ratio of the areas of two triangle is equal to the square of their perimeters.
Let A and A' represents the area of two triangles and P and P' represents their perimeter.
Then they are related as:

We are given:
A=72 dm^2 , A'=50 dm^2
and P+P'=226 dm.-----------(1)
i.e. 
on taking square root on both the side we get:

Now putting the value of P in equation (1) we obtain:

Hence,
P=226-102.7272=123.2727
Hence, the perimeter of the triangles are:
P=123.2727 dm
P'=102.7272 dm
410.3ft^3. is correct
volume of the sphere with 3ft radius :

volume of the sphere with 5ft radius:

difference

good luck
The answer would be 60. By rounding, 14.2=14; 15.51=16; 14.99=15; 15.8=16.
14+15+16+16=61
Rounding: 61=60
9514 1404 393
Answer:
NQ = 13.5
Step-by-step explanation:
The diagonals of a parallelogram bisect each other. NQ is half of NP, so is ...
NQ = PN/2 = 27/2
NQ = 13.5
It is the same thing as the average you add everything up then you divide by the number of numbers you added together