$r= \frac{AB}{2} \\ \\A_{semi\:circle }=\frac{r^2\pi}{2} \\ \\A_{triangle}=A_{semi\:circle }=\frac{r^2\pi}{2} \\ \\A_{triangle}= \frac{2r\times h}{2} =rh \\ \\\frac{r^2\pi}{2}= rh \\ \\h=\frac{r\pi}{2} \\ \\ \tan{x}= \frac{h}{r} = \frac{\frac{r\pi}{2}}{r} =\frac{\pi}{2} \\ \\x=\arctan{\frac{\pi}{2}}
\\
\\x \approx 57.52^o$

7 0

3 years ago

Jake sold 36 tickets to the school fair and jeanne sold 15 what is the ratio

artcher [175]

12:5 is what you are looking for. 12/5 in fraction form

3 0

3 years ago

Please help! I know its either B or D but im not sure how to tell

DENIUS [597]

Answer:

Step-by-step explanation:

To find the equation of g(x), we can substitute the point into each of the equations.

A. g(x) = (1/4x)^2

1 = (1/4 * 2)^2

1 = (1/2)^2

1 = 1/4

This statement is false, so this is not the equation.

B. g(x) = 1/2 * x^2

1 = 1/2 * (2)^2

1 = 1/2 * 4

1 = 2

This statement is false, so this is not the equation.

C. g(x) = 2x^2

1 = 2 * 2^2

1 = 2 * 4

1 = 8

This statement is false, so this is not the equation.

D. g(x) = (1/2x)^2.

1 = (1/2 * 2)^2

1 = 1^2

1 = 1

This statement is true, so this is your answer.

Hope this helps!

6 0

3 years ago