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qaws [65]
2 years ago
9

F/m=v-u/t solve for T

Mathematics
1 answer:
Troyanec [42]2 years ago
7 0

Answer:

Step-by-step explanation:

\frac{F}{m} =\frac{v-u}{t} \\t=(v-u)*\frac{m}{F}

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Richard has a debt of $45. Express it in the form of absolute value.
leonid [27]

The absolute value of debt of $45 is 45 because a balance of $0 on an account means there is no debt, and a negative of 45 value represents the debt.

<h3>What is debt?</h3>

It is defined as the amount one party needs to pay to another party as the first party borrowed an amount that will be credited by the second party. Debt occurs when one party cannot be able to purchase something under normal circumstances.

As we know,

The absolute value of a negative account balance is equal to the amount of debt. A balance of $0 on an account means there is no debt. Credit is shown by a positive account balance.

Richard has a debt of $45.

The negative of 45 value represents the debt.

-$45 = debt

Absolute value = |-45| = 45

Thus, the absolute value of debt of $45 is 45 because a balance of $0 on an account means there is no debt, and a negative of 45 value represents the debt.

Learn more about the debt here:

brainly.com/question/17286021

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6 0
1 year ago
Please answer this question. I will give 100 points and brainliest. I need this done fast.
inessss [21]

Answer:

Answer is D) I and II only.

Step-by-step explanation:

If C=5/9(F-32) that means that the temperature is increased by 5/9 of a degree every one F degree. Also II is right because of the laws of thermodynamics.

Please Mark Me Brainliest!!!!

6 0
2 years ago
What is the solution to w - 9 1/2 = 15<br>24 1/2<br>6 1/2<br>23 1/2<br>5 1/2​
VladimirAG [237]

Answer:

Option A

Step-by-step explanation:

Convert mixed fraction to improper fraction.

\sf w - 9\dfrac{1}{2}=15\\\\     w - \dfrac{19}{2}=15

Now isolate 'w'

\sf w = 15 +\dfrac{19}{2}\\\\= \dfrac{15*2}{1*2}+\dfrac{19}{2}\\\\=\dfrac{30}{2}+\dfrac{19}{2}\\\\=\dfrac{30+19}{2}\\\\=\dfrac{49}{2}\\\\= 24\dfrac{1}{2}

3 0
2 years ago
Read 2 more answers
Find the distance between<br> 2-3i<br> And<br> 9+21i
Goryan [66]

2 - 3i is just another of writing (2, -3) in the cartesian plane, the 2-3i however is using the "imaginary axis" for the imaginary plane, is all however the imaginary axis is simply the equivalent of the y-axis.  Likewise 9+21i is just (9,21), so let's just use the distance formula.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{9}~,~\stackrel{y_2}{21})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[9-2]^2+[21-(-3)]^2}\implies d=\sqrt{(9-2)^2+(21+3)^2} \\\\\\ d=\sqrt{7^2+24^2}\implies d=\sqrt{49+576}\implies d=\sqrt{625}\implies d=25

3 0
3 years ago
Can someone help me with this i don’t understand at all
Sedbober [7]

Answer:

Use trig

Step-by-step explanation:

sin(55) = x/21

x = 21sin(55)

use calculator in degree mode

cos(55) = y/21

21cos(55) = y

5 0
2 years ago
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