the possibilities are probably b, using the elimination method
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
-3 = 9C/5 + 32
9C/5 = - 32 - 3
9C/5 = - 35
9C = - 175
C = -175/9
C = - 19.44
Answer:
mean is = 28.4
median is = 26
Step-by-step explanation:
mean- average
( 25+ 27+ 24+ 26+ 40 )/5 = 28.4
median- middle
25, 27, 24, 26, 40
{ rearrange }
24, 25, 26, 27, 40
the middle number is 26
Answer:
The probability that 12 people in your sample are carrying no cash is 0.0712
Step-by-step explanation:
n = 100
p(no cash) = 0.09
x = 12
By applying binomial distribution
P(x,n) = nCx*px*(1-p)(n-x)
P(x = 12) = 0.074.
The probability that 12 people in your sample are carrying no cash is 0.074.
n = 100
p(less than 50) = 0.78
x = 75
By applying binomial distribution
P(x,n) = nCx*px*(1-p)(n-x)
P(x = 75) = 0.0712
The probability that 12 people in your sample are carrying no cash is 0.0712
