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2 years ago

Write eighteen hundredths as a decimal.

Mathematics

1 answer:

arsen [322]2 years ago

7 0

If you write eighteen hundredths as a decimal it will be .18

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2 years ago

What is -5/6 + -5/6? (its ment to be a fraction)

maks197457 [2]

The answer is: " -5/3 " ; or, write as: " -1 ⅔ " .
_____________________________________________
Explanation:
_____________________________________________

(-5/6) + (-5/6) = (-5/6) <span>− (5/6) ;

------> {since: "adding a negative" is the same a "subtracting a positive"} ;

------> </span> (-5/6) − (5/6) = (-5 − 5) / 6 ;

= -10/6 = (-10/2) / (6/2) ;
_____________________________________________________
= " -5/3 " ; or, write as: " -1 ⅔ " .
_____________________________________________________

8 0

2 years ago

kylee bought a pack of 12 cookies one-third of the cookies are peanut butter. how many cookies in the pack are peanut butter?

jekas [21]

One-third of 12 cookies are peanut butter.

12/3 =4

4 cookies are peanut butter

6 0

2 years ago

Read 2 more answers

Match each set of vertices with the type of triangle they form.

Andrew [12]

Answer: The calculations are done below.

Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

$AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.$

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

$AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.$

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

$AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.$

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

$AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.$

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

$AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.$

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0

2 years ago

Read 2 more answers

What is the area of this triangle in the coordinate plane? 5 units² 6 units² 7 units² 12 units² A graph with a triangle drawn be

____ [38]

Answer:

6 units²

Step-by-step explanation:

The coordinates (1,1) (1,4) (5,1) form a right triangle as shown in the graph below

The base is is (1,1) and (5,1) so the length is 5-1 or 4 units

The height is (1,1) and (1,4) so the height is 4-1 or 3 units

Area of a triangle is given by

A = 1/2 bh

= 1/2 (4*3)

= 1/2 *12

= 6 units^2

8 0

3 years ago