Ca + 2HCl = CaCl₂ + H₂
c=4.50 mol/l
v=2.20 l
n(HCl)=cv
m(Ca)/M(Ca)=n(HCl)/2
m(Ca)=M(Ca)cv/2
m(Ca)=40g/mol·4.50mol/l·2.20l/2=198 g
198 grams of Ca are needed
True final answer to this question
Sometimes they might not know
2.55 moles H20 will be produced
It would form into NaCl because Na has a +1 charge while Cl has a -1 charge.
