The volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L
<h3>Dilution formula</h3>
M₁V₁ = M₂V₂
Where
- M₁ is the molarity of stock solution
- V₁ is the volume of stock solution
- M₂ is the molarity of diluted solution
- V₂ is the volume of diluted solution
<h3>Data obtained from the question </h3>
- Molarity of stock solution (M₁) = 24.7 mol/L
- Volume of diluted solution (V₂) = 8 L
- Molarity of diluted solution (M₂) = 10 mol/L
- Volume of stock solution needed (V₁) = ?
<h3>How to determine the volume needed </h3>
The volume of the methanol necessary to prepare the solution can be obtained as illustrated below:
M₁V₁ = M₂V₂
24.7 × V₁ = 10 × 8
24.7 × V₁= 80
Divide both side by 24.7
V₁ = 80 / 24.7
V₁ = 3.2 L
Thus, the volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L
Learn more about dilution:
brainly.com/question/15022582
#SPJ1
<em>Answer:</em>
![\boxed{N_t =0.1953125 \: grams}](https://tex.z-dn.net/?f=%5Cboxed%7BN_t%20%3D0.1953125%20%5C%3A%20grams%7D)
Explanation:
<em>Formula:</em>
![N_t = N_0( { \frac{1}{2} })^{ \frac{t}{t_ \frac{1}{2} } }](https://tex.z-dn.net/?f=N_t%20%3D%20N_0%28%20%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%29%5E%7B%20%5Cfrac%7Bt%7D%7Bt_%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%7D%20)
Where Nt is the amount of substance remaining after time t,
N0 is the amount of substance at time t = 0,
t is the time at which we have to find out how much substance disintegrated from t = 0 to t = t
& t_1/2 is the half life corresponding radioactive sample.
<em>Given:</em>
N0 = 200g
t= 40 days
t1/2 = 4 days
<em>To find:</em>
Nt =?
<em>Solution:</em>
Substituting given data in above formula,
![N_t = N_0( { \frac{1}{2} })^{ \frac{t}{t_ \frac{1}{2} } } \\ N_t = 200( { \frac{1}{2} })^{ \frac{40}{4 } } \\ N_t = 200 \times 0.0009765625 \\ \boxed{N_t =0.1953125 \: grams}](https://tex.z-dn.net/?f=N_t%20%3D%20N_0%28%20%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%29%5E%7B%20%5Cfrac%7Bt%7D%7Bt_%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%7D%20%5C%5C%20N_t%20%3D%20200%28%20%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%29%5E%7B%20%5Cfrac%7B40%7D%7B4%20%7D%20%7D%20%5C%5C%20N_t%20%3D%20200%20%5Ctimes%200.0009765625%20%5C%5C%20%5Cboxed%7BN_t%20%3D0.1953125%20%20%5C%3A%20grams%7D%20)
<u>Thanks for joining brainly community!</u>
Both atoms must be non-metals,
Both atoms must have an incomplete outer energy level / shell of electrons
Air is a mixture
hope this helps :)
Answer:
1894.4g
Explanation:
We just multiply
the mass of mol with the number of mol
1.85 •1024=1894.4g