A. Intermediate is the answer
Answer:
Option a → 111.9 g
Explanation:
The reaction is this:
2KClO₃ → 2KCl + 3O₂
2 moles of chlorate decompose to 2 moles of chloride and 3 moles of oxygen. Ratio is 2:2.
If I use 1.5 moles of chlorate I'll get the same moles of chloride by the decomposition.
Let's convert the moles to mass: 1.5 mol . 74.6 g / 1mol = 11.9 g
Copper (Cu) and silver (Ag) would not liberate hydrogen because they are less reactive than hydrogen since their standard reduction potential is higher.
<em>6.13 x 10²⁴ atoms of Na = (6.13 * 10²⁴)/6.023 * 10²³ moles of Na = 10.17 moles</em>
