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Gre4nikov [31]
3 years ago
9

At 524 mm Hg and 35 °C, a sample of gas occupies a volume of 275 ml. The gas is transferred to a 325-ml flask and the temperatur

e is reduced to 5 °C
What is the pressure of the gas in the flask in mmHg?
Chemistry
1 answer:
Deffense [45]3 years ago
6 0

Answer:

400.197mmHg

Explanation:

P1V1 / T1 = P2V2 / T2

Where P1=524 mm Hg V1 =275 ml T1 = 35°C +273 = 308k

V2= 325-ml T2= 5°C+273 = 278k , P2= ?

Substituting the values into the formula.

524 mm Hg ×275 ml /308k = P2×325-ml/278k

Cross multiply

524 mm Hg ×275 ml×278k=308k×P2×325-ml

40059800= 100100×P2

P2 = 40059800/100100

P2= 400.197mmHg

Hence, the second pressure will be 400.197mmHg

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7 0
3 years ago
What is the balanced equation for the reaction of aqueous cesium sulfate and aqueous barium perchlorate?
Aleksandr-060686 [28]

Answer:

The balanced chemical reaction is given as:

Cs_2SO_4(aq)+Ba(ClO_4)_2(aq)\rightarrow BaSO_4(s)+2CsClO_4(aq)

Explanation:

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The balanced chemical reaction is given as:

Cs_2SO_4(aq)+Ba(ClO_4)_2(aq)\rightarrow BaSO_4(s)+2CsClO_4(aq)

According to reaction, 1 mole of cesium sulfate reacts with 1 mole of barium perchlorate to give 1 mole of a white precipitate of barium sulfate and 2 moles of cesium perchlorate.

3 0
3 years ago
Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a
coldgirl [10]

The final temperature, t₂ = 30.9 °C

<h3>Further explanation</h3>

Given

24.0 kJ of heat = 24,000 J

Mass of calorimeter = 1.3 kg = 1300 g

Cs = 3.41 J/g°C

t₁= 25.5 °C

Required

The final temperature, t₂

Solution

Q = m.Cs.Δt

Q out (combustion of compound) = Q in (calorimeter)

24,000 = 1300 x 3.41 x (t₂-25.5)

t₂ = 30.9 °C

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3 years ago
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