now, the angle of θ, can only have a "y" value that is positive on, well, y is positive at 1st and 2nd quadrants
and "x" is positive only in 1st and 4th quadrants
now, that angle θ, can only have those two fellows, "y" and "x" to be positive, only in the 1st quadrant, and also both to be negative on the 3rd quadrant.
and that those two fellows, can also be both negative in the 3rd quadrant
3/1 = 3, and -3/-1 = 3
so, the solutions can only be "3", when both "y" and "x" are the same sign, and that only occurs on the 1st and 3rd quadrants
Answer:
the distance is 16
Step-by-step explanation:
Hi there!
We are given point A (-4,-13) and point B (-4,3). We need to find the distance between those two points
the distance formula is given as 
where (
,
) and (
, 
) are points
we are given 2 points, which is what we need for the formula. However, let's label the values of the points to avoid any confusion
=-4
=-13
=-4
=3
now substitute those values into the formula. Remember: the formula uses SUBTRACTION.
simplify
now add the values inside the parenthesis that are under the radical
raise everything under the radical to the second power
add under the radical
now take the square root of 256
=16
so the distance between point A and point B is <u>16</u>
Hope this helps! :)
-3(2x-4)+8x-8
-6x+12+8x-8
2x+4
x=2
Multiply both sides by three to get 2x=30
Then divide both sides by 2 to get x=15
Solve for f:(i - 47/12) + f = 18
(i - 47/12) + f = f + (-47/12 + i):
f + (-47/12 + i) = 18
Subtract -47/12 + i from both sides:
Answer: f = 263/12 - i
