Question

Lincoln is wrapping a rectangular shaped present. The length of the present is 4 inches, the width is 8 inches and the height is 15 inches. How much wrapping paper will Lincoln need?

Answer 1

Step-by-step explanation:

To find the area of the wrapping paper required,

we must find the Total Surface Area of the box

As we know, the TSA of a cuboid= 2 (lh+bh+lb)

Here,

Total Surface Area of the cuboid=

$2(4 \times 8 + 8 \times 15 + 15 \times 4)$

$= 2(32 + 120 + 60)$

$= 2(212)$

$= 414 \: inches^2$