Answer:
y = (x -2)^2 +4
Step-by-step explanation:
The vertex form of the equation of a parabola is ...
y = a(x -h)^2 +k
for vertex (h, k) and vertical scale factor "a". When a > 0, the parabola opens upward.
One equation for your parabola could be ...
y = (x -2)^2 +4
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In standard form this one is ...
y = x^2 -4x +8
Pretty Sure Its B I had this question Too
Answer: Hi there
To find the last term in order to obtain the perfect square, take the middle term, divide it by 2, and take its square.
10 ÷ 2 = 5
5^2 = 25
Thus, the equation would be x^2 + 10x + 25
The answer is 25
Maybe mark Brainliest
:D
Answer:
(2.4, -1)
Step-by-step explanation:
Using midpoint formula plug in the info (x1+x2)/2, (y1+y2)/2
Answer:
○ 
Step-by-step explanation:
![\displaystyle 4 = 2\sqrt{25} - 6 \\ 4 = 2[5] - 6 \\ \\ 4 = 10 - 6](https://tex.z-dn.net/?f=%5Cdisplaystyle%204%20%3D%202%5Csqrt%7B25%7D%20-%206%20%5C%5C%204%20%3D%202%5B5%5D%20-%206%20%5C%5C%20%5C%5C%204%20%3D%2010%20-%206)
I am joyous to assist you at any time.
