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SSSSS [86.1K]
3 years ago
15

In the rhombus, m∠1=8y-6. Find the value of y?

Mathematics
1 answer:
lesya [120]3 years ago
8 0

Answer:

The value of y = 12

Step-by-step explanation:

<u>Points to remember </u>

In a rhombus the diagonals are bisect each other perpendicularly.

<u>To find the value of y</u>

From the figure we can see a rhombus. The <1 is a right angle.

m<1 = 90

Therefore,  8y - 6 = 90°

8y = 90  + 6

8y = 96

y = 86/8

y = 12

Therefore the value of y = 12

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Which description is represented by a discrete graph?
ozzi

Answer:A)

Kiley bought a platter for $19 and several matching bowls that were $8 each. What is the total cost before tax

here x will be number of bowl which can only be dicrete value e.g 1 , 2 , 3 , 4 ...

Step-by-step explanation:

A discrete graph is a series of scatter plot points. It means point on graph aren't continuous manner.

A continuous function allows the x-values to be ANY points in the interval, including fractions, decimals, and irrational values. A discrete function allows the x-values to be only certain points in the interval, only integers or whole numbers.

Example

Number of student, x

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Step-by-step explanation:

8 0
3 years ago
What does 1.2h-2.8=2 in one step equation form ?
nekit [7.7K]

Answer:

h=4

Step-by-step explanation:

1.2h-2.8=2

1.2h=2+2.8

1.2h=4.8

h=4.8/1.2

h=4

8 0
2 years ago
Martens got a small aquarium forgot her birthday. The aquarium is a right rectangular prism 18.5cm long by 15cm wide. Martens pu
sp2606 [1]

Answer:

Depth of Martens aquarium water = 14 cm.

Step-by-step explanation:

Given:

An aquarium,which is a right rectangular prism.

Length of the aquarium, l = 18.5 cm

Width of the aquarium, b = 15 cm

Volume of the aquarium, V = 3885 cm cubes

We have to find the depth of the aquarium.

Let the depth be h cm.

Note:

Volume of the rectangular prism,V=lbh.

⇒ V = l\times b\times h

⇒ h=\frac{V}{l\times b}

⇒ Plugging the values.

⇒ h=\frac{3885\ cm^3}{18.5\ cm\times 15\ cm}

⇒ h=14 cm

So,

The depth of the aquarium water is 14 cm.

4 0
3 years ago
Recently a sample of 36 pieces of thread showed a mean breaking strength of 8.93 oz. Can one conclude at a significance level of
Deffense [45]

Complete Question

It has been found from experience that the mean breaking strength of a particular brand of thread is 9.72 oz with a standard deviation of 1.4 oz. Recently a sample of 36 pieces of thread showed a mean breaking strength of 8.93 oz. Can one conclude at a significance level of (a) 0.05, (b) 0.01 that the thread has become inferior?

Answer:

At both \alpha = 0.05 and  \alpha  =  0.01  the conclusion is that the thread has become inferior

Step-by-step explanation:

From the question we are told that

      The population  mean is  \mu =  9.72 \ oz

      The standard deviation is  \sigma  = 1.40\  oz

       The sample size  is  n =  36

        The sample mean is  \= x  =  8.93 \ oz

The  null hypothesis is  H_o  :  \mu =  9.72 \  oz

The  alternative hypothesis is  H_a  :  \mu <  9.72 \ oz

     Generally the test statistics is mathematically represented as

             t =  \frac{ \= x - \mu }{ \frac{\sigma }{ \sqrt{n} } }

=>        t =  \frac{ 8.93 -9.72}{ \frac{ 1.4 }{ \sqrt{36} } }

=>      t = -3.33

So  

    The  p-value obtained from the z- table is  

            p-value  =  P( Z  <  -3.39) = 0.00034946

So at  \alpha  =  0.0 5

     p-value  <  \alpha

So we reject the null hypothesis,hence we conclude that the thread has become inferior

  So at  \alpha  =  0.0 1

     p-value  <  \alpha

So we reject the null hypothesis,hence we conclude that the thread has become inferior

5 0
3 years ago
How do you find all zeros by factoring
TiliK225 [7]
<span>Set the function equal to 0.Using "educated guessing", find two integers whose product equals c and whose sum equals b. These integers are always factors of c.Form a product of factors containing the variable and each of the integers found.<span>Set each factor equal to 0 and solve to find the Zeros.

</span></span><span>http://sites.csn.edu/istewart/Math126/zeros_factor/zeros_factor.htm
</span>
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2 years ago
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