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2 years ago

6-2x = 5x - 9x + 14.

Mathematics

2 answers:

prisoha [69]2 years ago

6 0

Answer:

x=4

Step-by-step explanation:

$6-2x=5x-9x+14\\6-2x=-4x+14\\6=-2x+14\\-8=-2x\\4=x$

torisob [31]2 years ago

4 0

Answer:

X= 4

Step-by-step explanation:

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N =⟨−2, −1⟩ and D=<img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%260%5C%5C4%261%5C%5C%5Cend%7Barray%

zepelin [54]

Answer:

-9

Step-by-step explanation:

-3(-2) + 0(-1)

4(-2) + 1(-1)

6 + 0

-8 + -1

-9

*don't forget to add brackets on each side of every calculation okay :)

5 0

2 years ago

Need help *URGENT* 7th grade Vertical Angles

Blababa [14]

Answer:

EBC = 90

FBG = 25

ABF = 115

ABG = 140

EBG = 50

Hope that helped :)

7 0

2 years ago

If Shape 1 is a scale copy of shape 2, What side corresponds of side AB?

igor_vitrenko [27]

Answer:

the answer is D. WX

Step-by-step explanation:

just look at the figure

6 0

2 years ago

In the diagram below, assume that all points are given in rectangular coordinates. Determine the polar coordinates for each poin

Korolek [52]

Step-by-step explanation:

We have cartisean points. We are trying to find polar points.

We can find r by applying the pythagorean theorem to the x value and y values.

$r {}^{2} = {x}^{2} + {y}^{2}$

And to find theta, notice how a right triangle is created if we draw the base(the x value) and the height(y value). We also just found our r( hypotenuse) so ignore that. We know the opposite side and the adjacent side originally. so we can use the tangent function.

$\tan(x) = \frac{y}{x}$

Remeber since we are trying to find the angle measure, use inverse tan function

$\tan {}^{ - 1} ( \frac{y}{x} ) =$

Answers For 2,5

${2}^{2} + {5}^{2} = \sqrt{29} = 5.4$

So r=sqr root of 29

$\tan {}^{ - 1} ( \frac{5}{2} ) = 68$

So the answer is (sqr root of 29,68).

For -3,3

${ -3 }^{2} + {3}^{2} = \sqrt{18} = 3 \sqrt{2}$

$\tan {}^{ - 1} ( \frac{3}{ - 3} ) = - 45$

Use the identity

$\tan(x) = \tan(x + \pi)$

So that means

$\tan(x) = 135$

So our points are

(3 times sqr root of 2, 135)

For 5,-3.5

${5}^{2} + {3.5}^{2} = \sqrt{37.25}$

$\tan {}^{ - 1} ( \frac{ - 3.5}{ - 5} ) = 35$

So our points are (sqr root of 37.25, 35)

For (0,-5.4)

${0}^{2} + { - 5.4}^{2} = \sqrt{} 29.16 = 5.4$

So r=5.4

$\tan {}^{ - 1} (0) = undefined$

So our points are (5.4, undefined)

4 0

2 years ago

Five sixth-grade classes collected canned food for the local food bank. Each class collected a different number of cans. Use the

tekilochka [14]

Answer:

308, 398, 421, 433, 570

Step-by-step explanation:

To start we know the smallest is 308 cans, so that is the first class.

Next, it says the range is 262. The range is maximum minus the minimum. Since we know the minimum(308), that means 308 + 262 = 570 and 570 is the maximum or the class with most collected cans.

Then, it says the median or the middle number is 421, the middle number in a class is 3. So, the third class collected a total of 421 cans.

After that, it says the two classes in the three hundred, or the first and second class, has a total of 706 cans. So, if we do 706 - 308 we get the second class. Which collected 398 cans.

Finally, it says the total all the class collected is 2130. So, if we add all the values we have know and subtract it from the total of all the class we get the missing class or the fourth class. So, 308 + 398 + 421 + 570 = 1697, and 2130 -1697 = 433. Which the fourth class.

Least to greatest:

308

398

421

433

570

3 0

2 years ago