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BabaBlast [244]
4 years ago
6

The diameter of an ice skating rink is 44 feet. In terms of π, what is the area of the rink to the nearest square yard? (9 ft2 =

1 yd2)
Mathematics
2 answers:
Dmitry [639]4 years ago
8 0

Answer:

B. 54π yd^2

Step-by-step explanation:

On god it is right trust mee!    

Over [174]4 years ago
7 0

Answer: Our required area is 54π sq. yd.

Step-by-step explanation:

Since we have given that

Diameter of an ice skating = 44 feet

Radius of an ice skating = 22 feet

as we know the formula for area :

Area would be

\pi r^2\\\\=\pi \times 22^2\\\\=484\pi\ ft^2

As we know that

9 sq ft = 1 sq yd

So, it becomes,

\dfrac{484\pi}{9}=53.77\pi\ yd^2\approx 54\pi\ yd^2

Hence, our required area is 54π sq. yd.

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