Question

The diameter of an ice skating rink is 44 feet. In terms of π, what is the area of the rink to the nearest square yard? (9 ft2 = 1 yd2)

Answer 1

Answer:

B. 54π yd^2

Step-by-step explanation:

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Answer 2

Answer: Our required area is 54π sq. yd.

Step-by-step explanation:

Since we have given that

Diameter of an ice skating = 44 feet

Radius of an ice skating = 22 feet

as we know the formula for area :

Area would be

$\pi r^2\\\\=\pi \times 22^2\\\\=484\pi\ ft^2$

As we know that

9 sq ft = 1 sq yd

So, it becomes,

$\dfrac{484\pi}{9}=53.77\pi\ yd^2\approx 54\pi\ yd^2$

Hence, our required area is 54π sq. yd.