The diameter of an ice skating rink is 44 feet. In terms of π, what is the area of the rink to the nearest square yard? (9 ft2 = 1 yd2)
2 answers:
Answer:
B . 54π yd^2
Step-by-step explanation:
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Answer: Our required area is 54π sq. yd.
Step-by-step explanation:
Since we have given that
Diameter of an ice skating = 44 feet
Radius of an ice skating = 22 feet
as we know the formula for area :
Area would be
As we know that
9 sq ft = 1 sq yd
So, it becomes,
Hence, our required area is 54π sq. yd.
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