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Vedmedyk [2.9K]
3 years ago
13

Pls help me with this question

Mathematics
1 answer:
allochka39001 [22]3 years ago
3 0

Answer:

Step-by-step explanation:

For the first question the answer is 50(0.2 + 1)^2 = 72

For the second question it is y = 32

Step-by-step explanation:

In case you need to see how i got it...it's below

For number 1, y is proportional to (x + 1)^2

The equation would be y(x +1)^2 = k(the constant). Then I substituted numbers you gave me in the equation which was : 50(0.2 + 1)^2 = k(72)

For number 2 I used this equation: y (x + 1)^2 = 72. I substituted x for 0.5. The equation will be: y(0.5 + 1)^2 = 72. Then I got 32 for y.

Hope this helps:) i am the best lil kissman

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Answer:

New value =

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39 - (3% × 39) =

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Step-by-step explanation:

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Step-by-step explanation:

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If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.
oksian1 [2.3K]

Answer:

NK = 15

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KL = 19.85

\angle JKM =49

\angle JML =41

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Step-by-step explanation:

Given

MK = 30

NL = 13

\angle MKL = 41

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

NK = \frac{1}{2} * MK

NK = \frac{1}{2} * 30

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Solving (b): JL

JL is a diagonal, and it is twice of NL.

JL = 2 * NL

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Solving (c): KL

To solve for KL, we consider triangle KNL where:

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KL^2 = 394

KL = \sqrt{394

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Solving (d - h):

To do this, we consider triangle JKN

\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90 -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41

Similarly:

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49

So:

\angle JKM =49

\angle JML =41

\angle MLK = \angle MLJ + \angle JLK

\angle MLK = 49 + 41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

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3 years ago
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