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disa [49]
3 years ago
9

In the figure, ABC DFE. What is the perimeter of ABC in inches?

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

Step-by-step explanation: 54in

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What is the area of an isosceles right triangle whose hypotenuse is 5 √2 m long?
tangare [24]

Answer:

Sides other than hypotenuse of an isosceles triangle are equal.

Let the other two sides be x each.

Using pythagoras theorem

x

2

+x

2

=(5

2

)

2

2x

2

=50

⇒x

2

=25

⇒x=5cm

So the other two sides are 5cm each.

5 0
2 years ago
What is equivalent to 40/64
Nadya [2.5K]

Answer: 5/8


Step-by-step explanation:


8 0
3 years ago
Can someone PLZ help me with this fast! I will award brainliest and 15 points!
Ray Of Light [21]
It is A and if you dont think i an right all you have to do is add and see what number is the closest

5 0
3 years ago
The length of a rectangle is 3 meters more than twice its width.The perimeter of the rectangle is 48 meters. Let W represent the
lord [1]
Perimeter of a rectangle: 2(l+w)

Let width be 'x'

Length is 3 meters more than twice 'x'
Length= 2x+3.

L= x
W = 2x+3


Formula =
2(x+2x+3)
2(3x+3)
6x+6.
6(x+1)
8 0
4 years ago
Write the equation for the quadratic function in standard form
Ede4ka [16]

Answer:

y=x^2+6x+7

Step-by-step explanation:

To write the quadratic in standard form, begin by writing it in vertex form

y = a(x-h)^2+k

Where (h,k) is the vertex of the parabola.

Here the vertex is (-3,-2). Substitute and write:

y=a(x--3)^2+-2\\y=a(x+3)^2-2

To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.

7=a((0)+3)^2-2\\7=a(3)^2-2\\7=9a-2\\9=9a\\1=a

The vertex form of the equation is y=(x+3)^2-2.

To write in standard form, convert vertex form through the distributive property.

y=(x+3)^2-2\\y=(x^2+6x+9)-2\\y=x^2+6x+7

8 0
4 years ago
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