<span>y=34x−52
34x - y - 52 = 0</span>
Answer:
The answer to your question is: D = non of the above
Step-by-step explanation:
Data
-4x - 4y = -5 (I)
x - 2y = 1 (II)
Process
Find the slopes of both lines
(I) -4x - 4y = -5
-4y = 4x + 5
y = 4/-4 x + 5/-4
y = - x + 5/4
(II) x - 2y = 1
- 2y = - x + 1
y = -1/-2 x + 1/-2
y = 1/2 x - 1/2
The slopes are different slope 1 = -1 and slope 2 = 1/2, so there is no relation between the lines.
Rounding it to the tens place so your answer for 12mm is going to be 10
You have Lagrangian
with partial derivatives (set equal to 0)
Solving the first four equations for
, respectively, we can substitute these solutions in terms of
into the fifth equation to find
, which in turn will lead to
. Denoting by
, we have
and substituting into the fifth equation yields
From either choice of
we arrive at
, i.e. exactly two critical points at
, for which we get a maximum value of 14 and minimum value of -14, respectively.