I think the correct answer is C. Less than 10% of rain falls in a dry desert. Desert biomes are known to be the driest of all types of biomes. It receives very or almost no rainfall. Precipitation in a dry desert is about 250 mm per year.
The correct answer is the last statement.
If the regulatory serine is mutated to alanine, then acetyl-CoA carboxylase will get activated spontaneously and will produce malonyl-CoA. The increased concentrations of malonyl-CoA will obstruct the oxidation of fatty acids by preventing the entry of fatty acids into the mitochondria.
It is because the AMP-activated protein kinase phosphorylates the serine residues of acetyl-CoA carboxylase to inactivate it. If a mutation occurs in such residues, then the AMPL cannot phosphorylate acetyl-CoA carboxylase and this enzyme will get activated spontaneously.
In such a situation, there will be more than sufficient production of malonyl-CoA, which will inhibit the admittance of more fatty acid getting inside the mitochondria; this will indirectly prevent the oxidation of fatty acids.
Answer:
The correct answer is - acidic conditions wouldn't trigger a change in the color of Alizarin yellow.
Explanation:
The growth of E. coli generally occurs at neutral pH, however, its growth is normal at acidic conditions as well. The change in the growth of E. coli is not able to detect by alizarin.
The phenol red turns yellow in the presence of an acid, and the change in pH in an alkaline environment can be detected by the red color of phenol red. Growth of E.coli will grow in pH of 10-12 . But, very slowly. The color change in alizarin is also apparent at pH 10.2 to 12 only.
