What's the solution to |1x-12| < 15

1 answer:

5 0

Start with |1x - 12| < 15. Add 12 to both sides. Then |1x - 12 + 12| < 15 + 12

Simplifying, |x| < 27. Then the two solutions are x < 27 and x > -27. In words, the solution set is the set of all x greater than -27 and less than +27.

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The line through (6,-6) with slope 1/2 in point-slope form ?

aleksandrvk [35]

Answer: $y + 6 = \frac{1}{2}(x - 6)$

Step-by-step explanation:

Point-slope formula: $y - y1 = m(x - x1)$

Plug in the numbers: $y - -6 = \frac{1}{2}(x-6)$

Clear the double negatives: $y + 6 = \frac{1}{2}(x - 6)$

8 0

3 years ago

Write the equation of a line that is perpendicular to y=7x−2 and passes through the point (14,8).(1 point) y=7x−90 y=10x−17 y=−1

True [87]

Answer:

$\huge\boxed{y=-\frac{1}{7}x+ 10}$

Step-by-step explanation:

In order to find the equation of this line, we need to note two things.

A) The slope of two lines that are perpendicular will be opposite reciprocals (that is, multiplying them gets us -1.)
B) We can substitute a point inside an incomplete equation to try and find a missing value.

So first, let's find the opposite reciprocal of 7 which will be the slope to this equation.