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ElenaW [278]
4 years ago
8

Jack and Andrea want to create a right triangle together using values of x and y and the polynomial identity to generate Pythago

rean triples. If Andrea picks a value of x = 2, and the hypotenuse of the resulting right triangle is 5, what natural number value of y did Jack pick?
Mathematics
1 answer:
Rasek [7]4 years ago
4 0
Y=2 thats your answer
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There are 60 students in a class among which 30 are boys. In another class there are 50 students among which 25 of them are boys
Leokris [45]

Answer:

A).= 1/2 probability of selecting girls.

B).= 1/2

Step-by-step explanation:

because there are 30 boys out of sixty which makes it half the class.

then theres 25 boys out of 50. therefore the answer is 1/2

6 0
4 years ago
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Use what you know about zeros of a function and end behavior of a graph to choose the graph that matches the function f(x)=(x-2)
Amiraneli [1.4K]

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Step-by-step explanation:

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4 years ago
Michael has 5 more comic books than double David's collection. If together they have a total of 128 comics, use the equation fro
Mumz [18]

Answer: Michael has 87 comic books while David has 41 comic books.

Step-by-step explanation:

Let x represent the number comic books that Michael has.

Let y represent the number of comic books that David has.

Michael has 5 more comic books than double David's collection. The expression would be

x = 2y + 5

If together they have a total of 128 comics, it means that

x + y = 128- - - - - - - - - -1

Substituting x = 2y + 5 into equation 1, it becomes

2y + 5 + y = 128

3y + 5 = 128

3y = 128 - 5

3y = 123

y = 123/3

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Substituting y = 41 into x = 2y + 5, it becomes

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5 0
3 years ago
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Svetllana [295]

Answer:

$19.45

Step-by-step explanation:

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8 0
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Answer:

Since n(1-p) < 10, it is not suitable to use a normal distribution.

Step-by-step explanation:

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In a binomial distribution with parameters n and p, the normal approximation is suitable is:

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In this question, we have that:

n = 17, p = 0.8. So

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n(1-p) = 17*0.2 = 3.4 -> No

So, since n(1-p) < 10, it is not suitable to use a normal distribution.

6 0
3 years ago
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