Answer:
igwif
Step-by-step explanation:
392e6×0273=2048
The independent variable is your input (x-value) and the dependent variable (y-value) depends on what the input is.
y = 10x
y is total money earned
x = number of lawns mowed
The first answer listed
Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120
Answer:
predictive value of a positive test = 18.18%
predictive value of a negative test = 94.03%
Step-by-step explanation:
Sensitivity = 60% = 0.6
Specificity = 70% = 0.7
Let True Positive = TP
True Negative = TN
False Negative = FN
Prevalence = 10% = 0.1
Three hundred people are screened, 
Total number of people having the disease, 
But TP = 1.5 FN
30 = 1.5 FN + FN
30 = 2.5 FN
FN = 30/2.5
FN = 12
TP = 1.5 FN = 1.5 * 12
TP = 18
81 + TN = 270
TN = 189
To calculate the Predictive value of positive test (PPT)
To calculate the Predictive value of negative test (PNT)
