(x + a)/(ax) = b/x a= 2b = 5(x + 2) /(2x) = 5/x cross multiplyx * (x+2) = (2x)*5x^2 + 2x = 10x x^2 - 8x = 0 x ( x -8) = 0We get two solutionsx = 0, 8the solution 0 is extraneousthe solution 8 is valid.
Answer:
26
Step-by-step explanation:
2*3*5-3(-2)+5(-2)
6*5+6-10
30+6-10
36-10
Your answer is 23/24
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