Solve using synthetic division. (−2x^3 + 5x^2 − x + 2) ÷ (x + 2)

The first digit of a string of 2002 digits is a 1. Any two-digit number formed by consecutive digits within this string is divis

Umnica [9.8K]

The largest possible last digit in the string of 2002 digits and number divisible by 19 or 31 is 9.

Given the first digit of a string of 2002 digits is 1 and the two digit number formed by consecutive digits within the string is divisible by 19 or 31.

We have to tell the last largest digit of such number.

Two digit numbers divisible by 19=19,38,57,76,95.

Two digit numbers divisible by 31=31,62,93,124

Number started with 1 =19

Last digit is 9

We have said that the number should be divisible by 19 or 31 not from both and started with 1.

Hence the largest possible last digit and number divisible by 19 or 31 in this string is 9.

Learn more about digits at brainly.com/question/26856218

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4 0

2 years ago

Complete this for me

GrogVix [38]

Answer:

Step-by-step explanation:

1 Kg of carrot = 40 p

1 1/2 Kg of carrot = 40 * $\frac{3}{2}$ = 20 * 3 = 60 p = £ 0.60

1 kg of potato = 52 p

3 kg of potato = 52 *3 = 156 p = £1.56

1 box of tea bags = 90 p

Number of boxes for £1.80 = 1.80 ÷ 0.90 = 2 boxes

4 packs of yogurt = £4.80

1 pack of yogurt = 4.80 ÷ 4 = £1.20

Total = 0.60 + 1.56 + 1.80 +4.80 = £ 8.76

8 0

3 years ago

If 2x – 1 is a factor of 16x4 24x3 + 2x + f, find f.

Nastasia [14]

Answer:

f = -5

Step-by-step explanation:

If 2x – 1 is a factor of 16x4 + 24x3 + 2x + f, find f.

If 2x - 1 = 16x⁴ + 24x³ + 2x + f, find f.

2x - 1 = 0

2x = 1

x = 1/2

Hence

f(1/2) = 16(1/2)⁴ + 24(1/2)³ + 2(1/2) + f

= 16(1/16) + 24(1/8) + 1 + f

= 1 + 3 + 1 + f

= 5+ f

f = -5

7 0

3 years ago

(Giving Brainliest♡)

frutty [35]

Answer:

15

Step-by-step explanation:

Hi there! :)

If you created 5 circles cut into thirds, you would create 15 1/3 pieces.

You can also use the KCF method to solve this!

7 0

3 years ago

Using triangle A B C as the pre-image and the origin as the center of dilation, which coordinate point is not a coordinate of a

Ostrovityanka [42]

Answer:

The correct option is:

begin ordered pair 4 comma 12 end ordered pair i.e. (4,12).

Step-by-step explanation:

We are given the coordinates of the point A,B and C of the triangle ΔABC as:

A(-1,3) , B(2,1) and C(-2,-1).

Now it is given that there is dilation of this triangle about the origin with a scale factor of 4.

This means that the change in the coordinates after the transformation is given by the rule:

(x,y) → (4x,4y)

As A → A' , B → B' and C → C'

Hence the coordinates A',B' and C' are given by:

A' are (4×-1,4×3)=(-4,12)

B' are (4×2,4×1)=(8,4)

and C' are (4×-2,4×-1)=(-8,-4).

Hence the coordinate point which is not a coordinate of dilation is:

begin ordered pair 4 comma 12 end ordered pair i.e. (4,12)

3 0

3 years ago