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Elina [12.6K]
3 years ago
14

Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.

Mathematics
2 answers:
saw5 [17]3 years ago
8 0

Answer: q=5\sqrt{5} , -5\sqrt{5}

Step-by-step explanation:

the roots (zeros) are the x values where the graph intersects the x-axis. to find the roots (zeros) , replace y with 0 and solve for x.

dalvyx [7]3 years ago
4 0

Answer:

Step-by-step explanation:

your equation shown above is set up incorrectly in order to solve this i need the right equation you must plug in each number to q to find the right solution

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for which of the following would it be appropriate to use positive integers for the domain of the function? select all that appl
Novosadov [1.4K]
Domain is the x-values. 

Scenarios where positive integers are appropriately used for the domain of the function:

<span>The function c(p) represents The cost for P people to attend the movies. (number of people can either be 0 going upwards)

</span><span>the function m(t) represents the miles driven over T hours (hours always start with 1.)

</span><span>the function t(m) represents the average high temperature for a given number of months (number of months always start with 1)

</span><span>the function p(w) represents the prophet of a farmer who sells whole watermelons (count of whole watermelon starts with 1)
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<span>the function h(n) represents the number of person-hours it takes to assemble n engines in a factory (number of engines always start with 1)</span>
7 0
3 years ago
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Is this correct?????
pickupchik [31]

Yes it’s correct my sister had something similar to that :)

7 0
3 years ago
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Given the four vectors in component form:
Kazeer [188]

Answer:

A

C

D

B

Step-by-step explanation:

3 0
2 years ago
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Can someone please help with this problem?​
stealth61 [152]

Answer:

measure of angle UMN is 160.

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8 0
3 years ago
The cosine of 23° is equivalent to the sine of what angle
Archy [21]

Answer:

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

(There are more values since we can go around the circle from 67 degrees numerous times.)

Step-by-step explanation:

You can use a co-function identity.

The co-function of sine is cosine just like the co-function of cosine is sine.

Notice that cosine is co-(sine).

Anyways co-functions have this identity:

\cos(90^\circ-x)=\sin(x)

or

\sin(90^\circ-x)=\cos(x)

You can prove those drawing a right triangle.

I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:

The sum of the angles is 180.

So 90+x+(missing angle)=180.

Let's solve for the missing angle.

Subtract 90 on both sides:

x+(missing angle)=90

Subtract x on both sides:

(missing angle)=90-x.

So the missing angle has measurement (90-x).

So cos(90-x)=a/c

and sin(x)=a/c.

Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).

We can do this also for cos(x) and sin(90-x).

cos(x)=b/c

sin(90-x)=b/c

This means sin(90-x)=cos(x).

So back to the problem:

cos(23)=sin(90-23)

cos(23)=sin(67)

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

6 0
3 years ago
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