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Elina [12.6K]
3 years ago
14

Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.

Mathematics
2 answers:
saw5 [17]3 years ago
8 0

Answer: q=5\sqrt{5} , -5\sqrt{5}

Step-by-step explanation:

the roots (zeros) are the x values where the graph intersects the x-axis. to find the roots (zeros) , replace y with 0 and solve for x.

dalvyx [7]3 years ago
4 0

Answer:

Step-by-step explanation:

your equation shown above is set up incorrectly in order to solve this i need the right equation you must plug in each number to q to find the right solution

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Steve opens a bank account. The amount, in dollars, in the account x weeks after the account is opened can be modeled by functio
ANTONII [103]

The missing options are:

A.\ f(20) =5,000

B.\ f(5000) = 20

C. In the xy plane, point (20, 5,000) is on the graph y = f(x).

D. In the xy plane, point (5,000,20) is on the graph y = f(x)

Answer:

A.\ f(20) =5,000

C. In the xy plane, point (20, 5,000) is on the graph y = f(x).

Step-by-step explanation:

Given

Represent amount with y and weeks with x

So, we have:

x = 20 when y = 5000

Required

Select 2 correct options

A point on a graph can be illustrated using  (x,y)

So, when x = 20 and y = 5000 ----- given

(x,y) implies that:

(x,y) = (20,5000)

We got (20,5000) by substituting 20 for x and 5000 for y

<em />

<em>From the list of given options, the above represented of (x,y) is illustrated in option C</em>

Represent (x,y) as a function, we have:

y = f(x)

Substitute values for x and y

5000 = f(20)

Reorder

f(20) = 5000

<em></em>

The above is illustrated in option A

<em>Hence, A and C answers the question</em>

3 0
3 years ago
Use the segment tool to draw a rectangle with a length of 4 units and a height of 2 units. one of the sides of the rectangle fal
Naya [18.7K]
The best and most correct answer among the choices provided by the question is the first choice. Move segment mus be done to draw the rectangle. I hope my answer has come to your help. God bless and have a nice day ahead!
6 0
3 years ago
What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?​
Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

 Given the equation:

\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}

- Using the Difference of squares formula (a^2-b^2=(a+b)(a-b)) we can simplify the denominator of the right side of the equation:

\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}

- Multiply both sides of the equation by (m+3)(3-m) and simplify:

\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}

- Multiply both sides by m-3:

(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)

- Apply Distributive property and simplify:

(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0

- Divide both sides of the equation by -6:

\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0

- Factor the equation and solve for "m":

(m-3)^2=0\\\\m=3

In order to verify it, you must substitute m=3 into the equation and solve it:

\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}

<em>NO SOLUTION</em>

7 0
3 years ago
For males in a certain town, the systolic blood pressure is normally distributed with a mean of 125 and a standard deviation of
makkiz [27]

95% have a systolic blood pressure between 109 and 141

Empirical rule states that for a normal distribution, 68% are within one standard deviation from the mean, 95% are within two standard deviation from the mean and 99.7% are within three standard deviation from the mean.

Given that mean (μ) = 125, standard deviation (σ) = 8.

68% are within one standard deviation = μ ± σ = 125 ± 8 = (117, 133)

95% are within two standard deviation = μ ± 2σ = 125 ± 2*8 = (109, 141)

95% have a systolic blood pressure between 109 and 141

Find out more on empirical rule at: brainly.com/question/10093236

5 0
2 years ago
The length of time for one individual to be served at a cafeteria is a random variable having an exponential distribution with a
Leya [2.2K]

Answer:

a) 0.25

b) 52.76% probability that a person waits for less than 3 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \lambda e^{-\lambda x}

In which \lambda = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

In this question:

m = 4

a. Find the value of λ.

\lambda = \frac{1}{m} = \frac{1}{4} = 0.25

b. What is the probability that a person waits for less than 3 minutes?

P(X \leq 3) = 1 - e^{-0.25*3} = 0.5276

52.76% probability that a person waits for less than 3 minutes

3 0
3 years ago
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