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vovangra [49]
3 years ago
14

Solve. x^2-15x+50 (x-5)(x+10) (x+5)(x+10) (x-10)(x-5) (x-10)(x+5)

Mathematics
1 answer:
fgiga [73]3 years ago
7 0
C.)<span>(x-10)(x-5)
and that is grouping the factors </span>
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Mikayla bought 5 skirts at $x each. Three of the five skirts came with a matching top for an additional $9 each write and simpli
Alisiya [41]
To find the total cost of Mikayla's purchase, we add together the costs of the skirts and tops. The costs of the skirts can be found be multiplying the quantity bought by the cost per skirt. Same goes for the tops.

5x + 3(9)

Simplified:

5x + 27
3 0
2 years ago
The heavyweight weight class in high school wrestling is from no less than 195lb and a maximum 285 LB write two inequalities to
rewona [7]

Answer:

<em>w >= 195 and w <= 285</em>

Step-by-step explanation:

No less than 195 lb means that 195 lb or more is allowed.

Let w = weight.

w >= 195

A maximum of 285 lb means that 285 lb or less is allowed.

w <= 285

Answer:  w >= 195 and w <= 285

3 0
3 years ago
Find the perimeter and area of the polygon shown below.
prohojiy [21]

Answer:

I would say it's d (sorry if im wrong)

3 0
2 years ago
Please help me answer as soon as possible. Thank u very much. Work is due tomorrow.
Firdavs [7]
The answer is 3 11/12 because the last one said RUNNING and it asked how much did he SWIM. Here is the math.

6/12 + 5/12 = 11/12

1+2=3

3 11/12. Hope this helped!
5 0
3 years ago
Read 2 more answers
USE THE FREQUENCY DISTRIBUTION TO DETERMINE THE FOLLOWING:A) THE TOTAL NUMBER OF OBSERVATIONS.B) THE WIDTH OF EACH CLASS.C) THE
lutik1710 [3]

A) The total number is the sum of all the frequencies

2+5+8+12+11+6=44

Answer: 44

B) The width is (upper limit - lower limit) / 2

(35-21) / 2 = 7

(50-36) / 2 = 7

(65-51) / 2 = 7

(80-66) / 2 = 7

(95-81) / 2 = 7

(110-96) / 2 = 7

Answer: the width is 7

C) The midpoint is the lower limit + the width

36+7=43

Answer: the midpoint is 43

D)The modal is the class with more frequency

In this case 66-80 with 12

Answer: class 66-80

E) We use the width formula

lower limit = 111

width = 7

upper = (width * 2) - lower

upper = (7 * 2) + 111

upper = 125

Answer: class 111-125

4 0
1 year ago
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