Question

What is the percent composition of chlorine in C2H2Cl2? Solve to the correct number of significant figures.

Answer 1

Answer:

$\%Cl=73.13\%$

Explanation:

Hello.

In this case, we can compute the percent composition of chlorine as shown below:

$\%Cl=\frac{2*m_{Cl}}{M_{C_2H_2Cl_2}}$

Whereas the atomic mass of chlorine is 35.45 g/mol and the molar mass of C₂H₂Cl₂ is 96.95 g/mol, thus, the percent composition turns out:

$\%Cl=\frac{2*35.45g/mol}{96.95g/mol}*100\%\\\\\%Cl=73.13\%$

Best regards.