What is the percent composition of chlorine in C2H2Cl2? Solve to the correct number of significant figures.

Chemistry

1 answer:

oksian1 [2.3K]3 years ago

4 0

Answer:

$\%Cl=73.13\%$

Explanation:

Hello.

In this case, we can compute the percent composition of chlorine as shown below:

$\%Cl=\frac{2*m_{Cl}}{M_{C_2H_2Cl_2}}$

Whereas the atomic mass of chlorine is 35.45 g/mol and the molar mass of C₂H₂Cl₂ is 96.95 g/mol, thus, the percent composition turns out:

$\%Cl=\frac{2*35.45g/mol}{96.95g/mol}*100\%\\\\\%Cl=73.13\%$

Best regards.

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The ratio of nitrogen to oxygen by mass in NO is 7.0:8.0. Identify the ratio of nitrogen to oxygen by mass in NO2 and N2O7 .

Rus_ich [418]

This problem is providing the ratio of nitrogen to oxygen by mass in nitrogen monoxide, NO, as 7.0:8.0 and asks for the same ratio but in NO₂ and N₂O₇. After doing the calculations, the results are 7.0:16.0 and 1.0:4.0 respectively.

<h3>Mass ratios:</h3>

In chemistry, one can calculate the mass ratios in chemical formulas according to the atomic mass of each atom. In such a way, one knows the mass ratio of nitrogen to oxygen in NO is 7.0:8.0 because we divide the atomic mass of nitrogen by oxygens:

$\frac{14}{16}=\frac{7.0}{8.0}$

Now, for chemical formulas with subscripts, one must multiply the atomic mass of the element by the subscript in the formula, which is the case of NO₂ and N₂O₇ as shown below:

$NO_2:\frac{14}{16*2}=\frac{14}{32} =\frac{7.0}{16.0} \\
\\
N_2O_7:\frac{14*2}{16*7}=\frac{28}{112} =\frac{1.0}{4.0}$