This
reaction is called the electrolysis of water. The balanced reaction is:
2H2O = 2H2 + O2
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We are given the amount of water for the electrolysis reaction. This
will be the starting point of our calculation.
45.6 grams H2O (1 mol H2O / 18.02 g H2O) (1 mol O2 / 2 mol H2O) = 1.27 mol O2
V = nRT/P = </span><span>1.27 mol O2 (0.08206 atm L / mol K) (301 K) / 1.24 atm
V = 25.20 L O2</span>
Answer:
See explanation
Explanation:
We know that the process of the oxidation of SO2 to SO3 is catalysed by NO2 gas. It occurs in two stages and i will show the balanced reaction equation of the both stages below;
Step 1
2NO2(g) + 2SO2(g) ------> 2NO(g) + 2SO3(g)
Step 2
2NO(g) + O2(g) -------> 2NO2(g)
So, the overall reaction equation is;
2SO2(g) + O2(g) ------> 2SO3(g)
Answer:
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