Answer:
46.8 g of water are produced in the reaction
Explanation:
The reaction is:
2HCl + Ca(OH)₂ → 2H₂O + CaCl₂
We have the moles of each reactant, so let's determine the limiting reagent.
Ratio is 2:1 and 1:2
2 moles of acid need 1 mol of hydroxide to react.
2.6 moles of acid would need (2.6 .1)/2 = 1.3 moles
I have 1.4 moles of Ca(OH)₂, so this is the excess. Therefore the limiting reactant is the acid. Let's verify it.
1 mol of hydroxide needs 2 moles of acid, to react.
1.4 moles of Ca(OH) would need, the double. Of course, 1.4 .2 = 2.8 moles.
I only have 2.6 moles of acid, and is not enough.
As we found out the limiting reactant, we can work with the equation.
2 moles of HCl produce 2 moles of water. Ratio is 1:1
Therefore 2.6 moles of HCl will produce 2.6 moles of H₂O
When we convert the moles to mass, we obtain:
2.6 mol . 18 g/mol = 46.8 g
