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baherus [9]
3 years ago
15

PLEASE HELP!!! DUE IN 1 HOUR!!

Mathematics
1 answer:
8090 [49]3 years ago
3 0

Answer:

i dont understand it

Step-by-step explanation:

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PLEASE PLEASE TRANSLATING A SENTENCE INTO AN EQUATION
wariber [46]

Answer:

j - 21 = 58

Step-by-step explanation:

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8 0
2 years ago
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Darrin surveyed a random sample of 10 students from his science class about their favorite types of TV shows. Five students like
Pepsi [2]

In my opinion, Darrin's inference is wrong because according to given question, "<em>Darrin surveyed a random sample of 10 students from his science class about their favorite types of TV shows.</em><em>"</em><em> </em>

This line provides the information that the survey is taken randomly. Also, if Darrin had taken some other students, then the ineference of other new students compared with previously surveyed students will be different.

This frankly tells that <em>t</em><em>h</em><em>e</em><em> </em><em>p</em><em>r</em><em>o</em><em>b</em><em>a</em><em>b</em><em>i</em><em>l</em><em>i</em><em>t</em><em>y</em><em> </em><em>i</em><em>s</em><em> </em><em>d</em><em>i</em><em>f</em><em>f</em><em>e</em><em>r</em><em>e</em><em>n</em><em>t</em><em> </em><em>a</em><em>l</em><em>w</em><em>a</em><em>y</em><em>s</em><em>.</em>

Therefore, Darrin's inference is wrong or invalid.

4 0
2 years ago
Which of the following are solutions to the equation below?
sladkih [1.3K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

Step-by-step explanation:

considering the equation

2x^2\:-\:4x\:-\:3\:=\:x

solving

2x^2\:-\:4x\:-\:3\:=\:x

2x^2-4x-3-x=x-x

2x^2-5x-3=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

solving

x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5+\sqrt{49}}{2\cdot \:2}

x=\frac{5+7}{4}

x=3

also solving

x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5-\sqrt{49}}{4}

x=-\frac{2}{4}

x=-\frac{1}{2}

Therefore,

                 \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

7 0
3 years ago
HELPP!!! WILL GIVE BRAINLIEST AND 5 STARS!!!
seraphim [82]

Answer:

F=73.74 degrees

Step-by-step explanation:

sin=opposite/hypotenuse

opp=24 hyp=25

sin(F)=24/25 (to find angle have to use inverse sin)

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6 0
3 years ago
In Brownsville Texas it is 80°F the temperature is expected to drop 1.5° each hour in Mesquite Texas is 94°F and the temperature
denis-greek [22]

Answer:

28 hours

Step-by-step explanation:

let the time period at which the temperature be equal in both Brownsville and Mesquite Texas be 'x'.

Given,

In Brownsville Texas, the temperature is expected to drop 1.5° each hour and In Mesquite Texas, the temperature is expected to drop 2° each hour.

Now, according to the question,

after 'x' hours,

⇒ 80° - 1.5°(x) = 94° - 2°(x)

⇒ 0.5°(x) = 14°

⇒ x = 28

Hence, Till 28 more hours the temperature in Mesquite Texas be greater than that in Brownsville.

3 0
3 years ago
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